Given:
There are two consecutive odd integers such that the square of the first added to 3 times the second, is 24.
To find:
Part a: Define the variables.
Part b: Set up an equations that can be solved to find the integers.
Part c: Find the integers.
Solution:
Part a:
Let x be the first odd integers. Then next consecutive odd integer is
, because the difference between two consecutive odd integers is 2.
Part b:
Square of first odd integers = 
Three times of second odd integers = 
It is given that the sum of square of first odd integers and three times of second odd integers is 24. So, the required equation is:

Part c:
The equation is:

It can be written as:



Splitting the middle term, we get




-6 is not an odd integer, so
and the first odd integer is 3.
Second odd integer = 
= 
= 
Therefore, the two consecutive odd integers are 3 and 5.
Answer:
that would be 1/4x
Step-by-step explanation:
Area = (5x + 4)(4x - 4)
= 20x^2 - 20x + 16x - 16
= 20x^2 - 4x - 16 Answer
Its G
Answer:
628 9/16 m
Step-by-step explanation:
distance = (100)(2)(22/7) = 628.57 m or 628 9/16
Answer:
Kindly check explanation
Step-by-step explanation:
H0 : μ ≥ 402
H1 : μ < 402
Test statistic :
n = 23
Sample Mean, x = 400
Variance = 900
σ = sqrt(900) = 30
Test statistic = (x - μ) ÷ σ/sqrt(n)
Test statistic = (400 - 402) ÷ 30/sqrt(23)
Test statistic = - 2 / 6.2554324
Test statistic = - 0.3197221
Test statistic = - 0.3197
Critical value :
Using the Tcritical value calculator
Tcrit; α = 0.025, df = n - 1 = 23 - 1 = 22
Tcritical = 2.074
Reject Null : if Test statistic ≤ Tcritical (left tail test)
Since ;
Test statistic ≤ Tcritical ; We reject the Null