The area of a rhombus is half of the product of the lengths of the diagonals.
area = (7.5 yd + 7.5 yd)(13 yd + 13 yd)/2
area = (15 yd)(26 yd)/2
area = 390 yd^2/2
area = 195 yd^2
Answer: 195
There are two ways to work this out: normal variables or using "imaginary" numbers.
Normal variables:
![(7+2i)(3-i)\\(7*3)+[7*(-i)]+(3*2i)+[2i*(-i)]\\21-7i+6i-2i^{2}\\\\21-i-2i^{2}](https://tex.z-dn.net/?f=%20%287%2B2i%29%283-i%29%5C%5C%287%2A3%29%2B%5B7%2A%28-i%29%5D%2B%283%2A2i%29%2B%5B2i%2A%28-i%29%5D%5C%5C21-7i%2B6i-2i%5E%7B2%7D%5C%5C%5C%5C21-i-2i%5E%7B2%7D)
Imaginary numbers:
Using the result from earlier:

Now since

, then the expression becomes:
Answer: what was the original price?
Step-by-step explanation:
Answer:
15 quarters, 10 nickels
Step-by-step explanation:


multiply the first equation by -0.25 and add the second equation to it

________________

has 10 nickels
has 15 quarters
10(.05) +15(0.25) = 0.5 + 3.75 = 4.25
Hope this helps
Answer:
Area=1/2bh
Given area of 36m^2
1/2(x)(x-1)=36
Multiply both sides by 2 to remove deminator
(x)(x-1)=72
X^2-x=72
X^2-x-72=0 then factor
(x-9)(x+8)=0
X=9,-8 however since area must be positive, take the absolute value of 8
1/2(9m*8m)=36m^2