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jeyben [28]
3 years ago
12

You guys know what 66÷124 is

Mathematics
2 answers:
azamat3 years ago
7 0

Answer: 0.53225806451

Mekhanik [1.2K]3 years ago
5 0
Answer:

0.53225806

Hope this helps!
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Help! I give brainlest. Problem is in Image
yawa3891 [41]

Answer:

65

Step-by-step explanation:

let's place 9 in place of p and 4 in place of q. I will use a star in place of that symbol for the sake of my convenience having to look for it, apologies.

9 \star 4  = 9^2-4^2 = 81-16 = 65

5 0
3 years ago
Read 2 more answers
Consider a bag of jelly beans that has 30 red, 30 blue, and 30 green jelly beans. a) How many color combinations of 15 beans hav
igor_vitrenko [27]

Answer:

680

Step-by-step explanation:

Number of red beans = 30

Number of Blue beans = 30

Number of green beans = 30

How many color combinations of 15 beans have at least 6 green beans?

Since at least 6 of the beans must be green,

Then (15 - 6) = 9

Then, the remaining 9 could be either red, blue or green.

Therefore, C(9 + (9 - 1), 3)

C(17, 3) = 17C3

nCr = n! ÷ (n-r)! r!

17C3 = 17! ÷ (17 - 3)! 3!

17C3 = 17! ÷ 14!3!

17C3 = (17 * 16 * 15) / (3 * 2)

17C3 = 4080 / 6

17C3 = 680 ways

5 0
3 years ago
Write of the following represents 6x^3/4 in radical form?
kenny6666 [7]

Answer:

6\sqrt[4]{x^3}[/tex]

Step-by-step explanation:

6x^3/4

is the same as

6 (x^3/4)

and the rule to change an exponent to a radical is power over root

so in this case, the power, 3 is over the root, 4

So it would be 6\sqrt[4]{x^3}[/tex]

3 0
3 years ago
You draw two cards at random from a standard deck. What is the probability of drawing at least one diamond?
hodyreva [135]
Well there are 52 cards in a deck. There are 13 of each kind of card. So 13/52 are diamonds
7 0
3 years ago
A square picture with a side length of 4 inches needs to be enlarged. The final area needs to be 81 square inches. Which equatio
maw [93]

Answer:

use photo math

Step-by-step explanation

its an app you can get on phone

4 0
4 years ago
Read 2 more answers
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