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victus00 [196]
2 years ago
5

Segment RS and segment ST below are congruent. Set up ban equation to find the value of x

Mathematics
1 answer:
borishaifa [10]2 years ago
3 0

Answer:

x = 11

Step-by-step explanation:

If the segments are congruent then

3x = x + 22 ➡ 3x - x = 22

2x = 22 divide both sides by 2

x = 11

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I need to know if it’s A B C OR D
Liula [17]

SOLUTION

Consider the property, opposite angle of a cyclic quadrilateral are supplementary

hence

\angle NMP+\angle NOP=180^0

Recall that

\begin{gathered} \angle NMP=\angle M=(8x-24)^0 \\ \text{and } \\ \angle NOP=\angle O=(4x)^0 \end{gathered}

Hnece, we have that

\begin{gathered} \angle M+\angle O=180^0(opposite\text{ angles of a cyclic quadrilateral)} \\ (8x-24)^0+4x^0=180^0 \end{gathered}

Then

\begin{gathered} 8x-24+4x=180 \\ 8x+4x-24=180 \\ 12x-24=180 \\ \text{Add 24 t o both sides } \\ 12x-24+24=180+24 \\ 12x=204 \\ \text{divide both sides by 12} \\ \frac{12x}{12}=\frac{204}{12} \\ \text{Then} \\ x=17 \end{gathered}

Hence

x=17

Since

\begin{gathered} \angle NOP=(4x)^0 \\ \text{substitute the value of x, we have } \\ \angle NOP=4\times17=68^0 \\ \text{Hence } \\ \angle NOP=68^0 \end{gathered}

Therefore

The measure of angle NOP is 68⁰

Answer; 68⁰ (The fourth Option )

5 0
1 year ago
6(2x+4)=4(3x+6) solve and show work
Afina-wow [57]

Answer:

0=0

Step-by-step explanation:

6(2x+4)=4(3x+6)

Step 1: Simplify both sides of the equation.

6(2x+4)=4(3x+6)

(6)(2x)+(6)(4)=(4)(3x)+(4)(6)(Distribute)

12x+24=12x+24

Step 2: Subtract 12x from both sides.

12x+24−12x=12x+24−12x

24=24

Step 3: Subtract 24 from both sides.

24−24=24−24

0=0

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The property x^axb makes it x^a+b so x^5x-2 ,

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Graph the exponential function<img src="https://tex.z-dn.net/?f=%20f%28x%29%3D%5Cfrac%7B1%7D%7B2%7D%5E%7Bx%7D%20%20" id="TexForm
tatyana61 [14]

f(x)=\left(\dfrac{1}{2}\right)^x\\\\for\ x=-3\to y=\left(\dfrac{1}{2}\right)^{-3}=2^3=8\to(-3,\ 8)\\\\for\ x=-2\to y=\left(\dfrac{1}{2}\right)^{-2}=2^2=4\to(-2,\ 4)\\\\for\ x=-1\to y=\left(\dfrac{1}{2}\right)^{-1}=2^1=2\to(-1,\ 2)\\\\for\ x=0\to y=\left(\dfrac{1}{2}\right)^0=1\to(0,\ 1)\\\\for\ x=1\to y=\left(\dfrac{1}{2}\right)^1=\dfrac{1}{2}\to\left(1,\ \dfrac{1}{2}\right)\\\\for\ x=2\to y=\left(\dfrac{1}{2}\right)^2=\dfrac{1}{4}

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Polygon ABCD goes through a sequence of rigid transformations to form polygon A′B′C′D′. The sequence of transformations involved
Sever21 [200]
Polygon ABCD goes through a sequence of rigid transformations to form polygon A′B′C′D′. The sequence of transformations involved is a reflection across the _Y-axis _, followed by a reflection across the line _y=-x__.
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