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3 years ago

Which shows the image of quadrilateral ABCD after the transformation R0, 90°?

Mathematics

2 answers:

saveliy_v [14]3 years ago

5 0

Answer:

Step-by-step explanation:

i jus took tha test

avanturin [10]3 years ago

4 0

Answer:

A'(0,-1), B'(1,0) , C'(3,-2), and D'(2,-3)

Step-by-step explanation:

The coordinates of rectangle ABCD are A(-1,0), B(0,-1), C(-2,-3), (-3,-2).

The mapping for a rotation through 90° clockwise about the origin is

$(x,y)\to ( - y,x)$

Therefore:

$A(-1,0)\to A'(0,-1)$

$B(0,-1)\to B'(1,0)$

$C(-2,-3)\to C'(3,-2)$

$D(-3,-2)\to D'(2,-3)$

Therefore the image rectangle has coordinates:

A'(0,-1), B'(1,0) , C'(3,-2), and D'(2,-3)

The first choice is correct.

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1 year ago

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nignag [31]

Answer:

The proof is given below.

Step-by-step explanation:

Given: ( the correct question and ans is as follow )

sin (x + y) = 3sin ( x - y)

To Prove

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Proof:

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Now we will take sin x . cos y to the left hand side and cos x . sin y to the right hand side,we get

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