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gogolik [260]
3 years ago
13

Jeremy caught 8 fish in a contest.

Mathematics
1 answer:
seraphim [82]3 years ago
6 0

Answer:

3.1 kg

Step-by-step explanation:

4.3+5.3+ 6.8+ 2.6 + 3.2 +4.4 +4.8= 31.4 kg

Last fish= y

(31.4 + y)÷ 8= 4.3125

31.4 + y= 4.3125 x 8

y= 34.5 - 31.4

∴ y= 3.1 kg

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When y is positive, the value of y squared is ALWAYS greater than the value of y.
erica [24]
Yes true it's basically saying any positive number squared is bigger than the number being squared now give me brainliest
6 0
3 years ago
X + 4 + 3x = 72<br><br> Yall Know The Deal
Snezhnost [94]

Answer:

x = 17

Step-by-step explanation:

Combine like terms first:

x + 3x + 4 = 72 --> 4x + 4 = 72

Isolate the variable by subtracting 4 from both sides so you get

4x = 72 - 4

4x = 68

Divide both sides by 4 to get

x = 68/4

x = 17

3 0
3 years ago
Complete the statements about the graph of a function.
Tom [10]

Answer:

See below

Step-by-step explanation:

When a graph is symmetric about the origin, it is an odd function (Ex: y=x³)

When a graph is symmetric about the y-axis, it is an even function (Ex: y=x²)

A function is considered even if f(x) = f(−x) and it is considered odd if f(-x)=-f(x).

3 0
3 years ago
6(2y -1) -2(2y) = 14
xenn [34]
Answer: y = 5/2 or 2.5

Steps:
6(2y - 1) - 2(2y) = 14
12y - 6 - 4y = 14
8y - 6 = 14
8y = 20
y = 20/8
y = 5/2 or 2.5
5 0
3 years ago
Plot the points A(9, 11) and B(–3, –5). Find midpoint M of AB. Then show that AM = MB and AM + MB =AB
Alex_Xolod [135]

Answer:

The midpoint is (3, 3).

Step-by-step explanation:

We are given the two points A(9, 11) and B(-3, -5).

The midpoint is given by:

\displaystyle M=\Big(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\Big)

So:

\displaystyle M =  \Big( \frac{9+(-3) }{2}, \frac{ 11+(-5) }{2} \Big) = (3,3)

The midpoint is (3, 3).

We want to show that AM = MB.

We can use the distance formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2

The distance between A(9, 11) and M(3, 3) will then be:

AM=\sqrt{(9-3)^2+(11-3)^2}=\sqrt{6^2+8^2}=\sqrt{100}=10

And the distance between B(-3, -5) and M(3, 3) will be:

MB = \sqrt{ (3-(-3))^2 + (3-(-5))^2 } = \sqrt{(6)^2+(8)^2} = \sqrt{ 100 } = 10

So, AM = MB = 10.

Since AM = MB = 10, AM + MB = 10 + 10 = 20.

So, we want to prove that AB = 20.

By the distance formula:

AB=\sqrt{(9-(-3))^2+(11-(-5))^2}=\sqrt{12^2+16^2}}=\sqrt{400}=20\stackrel{\checkmark}{=}20

4 0
3 years ago
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