Step-by-step explanation:
y = 3 + 8x^(³/₂), 0 ≤ x ≤ 1
dy/dx = 12√x
Arc length is:
s = ∫ ds
s = ∫₀¹ √(1 + (dy/dx)²) dx
s = ∫₀¹ √(1 + (12√x)²) dx
s = ∫₀¹ √(1 + 144x) dx
If u = 1 + 144x, then du = 144 dx.
s = 1/144 ∫ √u du
s = 1/144 (⅔ u^(³/₂))
s = 1/216 u^(³/₂)
Substitute back:
s = 1/216 (1 + 144x)^(³/₂)
Evaluate between x=0 and x=1.
s = [1/216 (1 + 144)^(³/₂)] − [1/216 (1 + 0)^(³/₂)]
s = 1/216 (145)^(³/₂) − 1/216
s = (145√145 − 1) / 216
You add of the sides to get the perimeter.. 9 plus 9 is 18 and 5 plus 5 is 10. 10 plus 18 of 28. The perimeter of ABCD is 28.
I hope this helps.
Juan's least integer scores in both tests will be 85 and 100 respectively.
- Test average of his two scores is atleast 92
Let :
- Score on test 1 = b
- Score on test 2 = b + 15
Average score can be related thus:
- (Sum of score ÷ number of test) ≥ 92
- (b + b + 15) ÷ 2 ≥ 92
- (2b + 15) ÷ 2 = 92
- 2b + 15 = 184
- 2b = 184 - 15
- 2b = 169
- b = 169 ÷ 2
- b = 84.5
Therefore, since both scores are integers, his least scores on both tests will be ::
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