Question

Please help me with this question

Answer 1

Step-by-step explanation:

${ ({y}^{2} )}^{4} . \: {( {y}^{3}) }^{2}$

Since,

${ ({a}^{x} )}^{y} = {a}^{xy}$

Hence,

${y}^{2 \times 4} . {y}^{3 \times 2}$

$= {y}^{8} . {y}^{6}$

Since,

${a}^{x} . {a}^{y} = {a}^{x + y}$

Hence,

$= {y}^{8 + 6}$

$= {y}^{14} (ans)$