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2 years ago

Please help me with this question

Mathematics

1 answer:

Setler [38]2 years ago

6 0

Step-by-step explanation:

${ ({y}^{2} )}^{4} . \: {( {y}^{3}) }^{2}$

Since,

${ ({a}^{x} )}^{y} = {a}^{xy}$

Hence,

${y}^{2 \times 4} . {y}^{3 \times 2}$

$= {y}^{8} . {y}^{6}$

Since,

${a}^{x} . {a}^{y} = {a}^{x + y}$

Hence,

$= {y}^{8 + 6}$

$= {y}^{14} (ans)$

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Explain why 6^3x7^3=42^3 is correct.

Orlov [11]

Answer:

${6}^{3} \times {7}^{3} = {(6 \times 7)}^{3} = {42}^{3}$

Step-by-step explanation:

When two or more quantities have the same exponents, their bases can be multiplied together.

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3 years ago

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(-5) -2-8 + 1 1-5-2-8 helpp plisssssss

Hoochie [10]

Answer:

-14

Step-by-step explanation:

(-5)-2-8+1

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3 years ago

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Nick's dad wanted to measure the length of his backyard and asked Nick to do this with his footsteps. Since it was winter, they

Lerok [7]

Answer:

2244 cm

Step-by-step explanation:

The first first thing we must do is find the LCM of the following numbers

(51; 68) = 204.

This means that the first time they coincide is at 204.

Now, since his steps always coincide after 204

In Nick's case

Nick's 204 ÷ 51 = 4th step

and in the case of the father

204 ÷ 68 of his father = 3rd step.

Which means that in the 204 cm distance, there will be a total of 6 foot steps, except in the first 204 cm when your "initial" step is counted.

Replacing these values we have that the total distance will be:

67-1 (initial step) / (6 * 204) = 2244 cm

7 0

2 years ago

Which expression is equal to 5, ? A 542 B. 51 Cw D. 254

nirvana33 [79]

Answer:

don't understand the full question

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3 years ago

A particle moves on the hyperbola xy=18 for time t≥0 seconds. At a certain instant, y=6 and dydt=8. What is x that this instant?

professor190 [17]

Answer:

The value of x at this instant is 3.

Step-by-step explanation:

Let $x\cdot y = 18$ , we get an additional equation by implicit differentiation:

$x\cdot \frac{dy}{dt}+y\cdot \frac{dx}{dt} = 0$ (1)

From the first equation we find that:

$x = \frac{18}{y}$ (2)

By applying (2) in (1), we get the resulting expression:

$\frac{18}{y}\cdot \frac{dy}{dt}+y\cdot \frac{dx}{dt} = 0$ (3)

$y\cdot \frac{dx}{dt}=-\frac{18}{y}\cdot \frac{dy}{dt}$

$\frac{dx}{dt} = -\frac{18}{y^{2}} \cdot \frac{dy}{dt}$

If we know that $y = 6$ and $\frac{dy}{dt} = 8$ , then the first derivative of x in time is:

$\frac{dx}{dt} = -\frac{18}{6^{2}} \cdot (8)$

$\frac{dx}{dt} = -4$

From (1) we determine the value of x at this instant:

$x\cdot \frac{dy}{dt} = -y\cdot \frac{dx}{dt}$

$x = -y\cdot \left(\frac{\frac{dx}{dt} }{\frac{dy}{dt} } \right)$

$x = -6\cdot \left(\frac{-4}{8} \right)$

$x = 3$

The value of x at this instant is 3.

4 0

2 years ago