Answer:
Step-by-step explanation:
First you have to calculate CB in order to use sin law to calculate ∠A
CB=
CB=12.8(correct to nearest tenth)
After that, use sin law to calculate ∠A,
or
sinA=0.695...
A=44.079...
=44.1(corrext to the nearest tenth)
Is that clear enough for you?
Answer:
5/4324 = 0.001156337
Step-by-step explanation:
To better understand the hyper-geometric distribution consider the following example:
There are 100 senators in the US Congress, and suppose 60 of them are republicans so 100 - 60 = 40 are democrats).
We extract a random sample of 30 senators and we want to answer this question:
What is the probability that 10 senators in the sample are republicans (and of course, 30 - 10 = 20 democrats)?
The answer using the h-g distribution is:
Now, imagine there are 56 senators (56 lottery numbers), 6 are republicans (6 winning numbers and 50 losers), we extract a sample of 6 senators (the bettor selects 6 numbers). What is the probability that 4 senators are republicans? (What is the probability that 4 numbers are winners?).
<em>As we see, the situation is exactly the same,</em> but changing the numbers. So the answer would be
Now compute each combination separately:
and now replace the values:
and that is it.
If the decimal expression is preferred then divide the fractions to get 0.001156337
Answer:
The teacher should set the score 7 as the lowest passing grade.
Step-by-step explanation:
Let <em>X</em> = number of correct guesses.
All the questions are of true-false format.
The probability of getting a correct answer is, <em>p</em> = 0.50.
The total number of questions is, <em>n</em> = 10.
The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 10 and <em>p </em>= 0.50.
The probability mass function of <em>X</em> is:
Now the teaches chose the grading scheme such that the probability of passing a student who guesses on every question is less than 0.05.
Then the probability of failing such a students is at least 1 - 0.05 = 0.95.
Compute the probability distribution of <em>X</em>.
Consider the probability distribution attached below.
The value of <em>x</em> for which P (X ≤ x) is at least 0.95 is, <em>x</em> = 7.
So the teacher should set the score 7 as the lowest passing grade.
