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eimsori [14]
3 years ago
10

Solve (4x - 5) (x + 3) = 0. Please need help

Mathematics
1 answer:
MakcuM [25]3 years ago
5 0

Answer:

x= 5,-3

Step-by-step explanation:

(4x - 5) (x + 3) = 0.

4 {x}^{2}  + 3x - 5x - 15  = 0 \\  4{x}^{2} - 2x - 15 = 0

the \: roots \: are \:

5 and -3

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Answer:

The value of the slope is 4

The meaning of the slope is y/x

Step-by-step explanation:

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Miss logan leaves school at 15:55 it takes her 1 hour and 20 mins to get home what time does she arrive home? answer using 24 ho
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6 0
2 years ago
If A^2=A, which matrix is matrix A
Ronch [10]

Consider all options:

A.

\left[\begin{array}{cc}5&5\\-4&-4\end{array}\right] \cdot \left[\begin{array}{cc}5&5\\-4&-4\end{array}\right] =\left[\begin{array}{cc}5\cdot 5+5\cdot (-4)&5\cdot 5+5\cdot (-4)\\-4\cdot 5+(-4)\cdot (-4)&-4\cdot 5+(-4)\cdot (-4)\end{array}\right]=

=\left[\begin{array}{cc}5&5\\-4&-4\end{array}\right].

This option is true.

B.

\left[\begin{array}{cc}6&5\\5&6\end{array}\right] \cdot \left[\begin{array}{cc}6&5\\5&6\end{array}\right] =\left[\begin{array}{cc}6\cdot 6+5\cdot 5&6\cdot 5+5\cdot 6\\5\cdot 6+6\cdot 5&5\cdot 5+6\cdot 6\end{array}\right]=

=\left[\begin{array}{cc}61&60\\60&61\end{array}\right].

This option is false.

C.

\left[\begin{array}{cc}0.5&-0.5\\-0.5&0.5\end{array}\right] \cdot \left[\begin{array}{cc}0.5&-0.5\\-0.5&0.5\end{array}\right] =\left[\begin{array}{cc}0.5\cdot 0.5+(-0.5)\cdot (-0.5)&0.5\cdot (-0.5)+(-0.5)\cdot 0.5\\-0.5\cdot 0.5+0.5\cdot (-0.5)&-0.5\cdot (-0.5)+0.5\cdot 0.5\end{array}\right]=

=\left[\begin{array}{cc}0.5&-0.5\\-0.5&0.5\end{array}\right].

This option is true.

D.

\left[\begin{array}{cc}0.5&0.5\\-0.5&0.5\end{array}\right] \cdot \left[\begin{array}{cc}0.5&0.5\\-0.5&0.5\end{array}\right] =\left[\begin{array}{cc}0.5\cdot 0.5+0.5\cdot (-0.5)&0.5\cdot 0.5+0.5\cdot 0.5\\-0.5\cdot 0.5+0.5\cdot (-0.5)&-0.5\cdot 0.5+0.5\cdot 0.5\end{array}\right]=

=\left[\begin{array}{cc}0&0.5\\-0.5&0\end{array}\right].

This option is false.

E.

\left[\begin{array}{cc}-6&-6\\5&5\end{array}\right] \cdot \left[\begin{array}{cc}-6&-6\\5&5\end{array}\right] =\left[\begin{array}{cc}-6\cdot (-6)+(-6)\cdot 5&-6\cdot (-6)+(-6)\cdot 5\\5\cdot (-6)+5\cdot 5&5\cdot (-6)+5\cdot 5\end{array}\right]=

=\left[\begin{array}{cc}6&6\\-5&-5\end{array}\right].

This option is false.

Answer: correct options are A and C.

8 0
3 years ago
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