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Tasya [4]
3 years ago
7

What is -5xy and 8xy​

Mathematics
2 answers:
Alenkinab [10]3 years ago
6 0

Answer:

3xy

Step-by-step explanation:

MrRa [10]3 years ago
3 0

Answer10:

Step-by-step explanation:

10

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Your Turn: Using the figure, a
Hatshy [7]
We are given:
\frac{a}{c} = \frac{d}{a}

First step is to get rid of fractions. We start by multiplying both sides by a.
\frac{a}{c} = \frac{d}{a} /*a \\

Now we cancel a on right side and we multiply both sides by c.
\frac{ a^{2}}{c} = \frac{da}{a} /*c \\ \frac{ a^{2}c}{c} = dc

After canceling c on the right side we are left with:
a^{2} = dc or a^{2} = cd
8 0
3 years ago
Farmer Brown and Farmer Green were talking over their fence one afternoon. Farmer Brown said, "If you gave me one of your cows,
qaws [65]

Farmer Brown has 5 cows and farmer Green has 7 cows

Step-by-step explanation:

Let the no. of cows farmer brown has be 'b'

Let the no. of cows farmer green has be 'g'

Given that,

B+1 = G-1

G = B + 2

G+1 = 2(B-1)

G+1 = 2B - 2

G = 2B -3

B + 2 = 2B - 3

2 + 3 = 2B - B

B = 5

G = B +2

G = 5 + 2

G = 7

Farmer Brown has 5 cows and farmer Green has 7 cows

3 0
3 years ago
Solve for t. 3/4t=14 <br> a. 1/3<br> b. 1<br> c. 4/3<br> d. 4
Molodets [167]
3/4t=14
t=56/3
hope this helps!
5 0
3 years ago
Read 2 more answers
Chin-Mae has a fishtank that measures 75 cm by 45 cm by 35 cm.
BARSIC [14]

Answer:

75+45+35

Step-by-step explanation:

Add all the numbers

3 0
3 years ago
how many gallons of 80% antifreeze solution must be mixed with 100 gallons of 10% antifreeze to get a mixture that is 70% antifr
ololo11 [35]
Let's say we'll mix "x" amount of the 80% solution, how much antifreeze is in it? well is just 80% of antifreeze, and the rest is something else.... what's 80% of "x"? so is (80/100)*x, or 0.8x.

likewise, the mixture will be a 70% solution, and let's say it adds up to "y" amount, so how much antifreeze is in it? well (70/100) * y or 0.7y.

\bf \begin{array}{lccclll}&#10;&\stackrel{gallons}{amount}&\stackrel{\%}{quantity}&\stackrel{antifreeze}{quantity}\\&#10;&------&------&------\\&#10;\textit{80\% sol'n}&x&0.80&0.8x\\&#10;\textit{10\% sol'n}&100&0.10&10\\&#10;------&------&------&------\\&#10;mixture&y&0.70&0.7y&#10;\end{array}

so whatever "x" is, we know that x + 100 = y.

and we know that 0.8x + 10 = 0.7y.

\bf \begin{cases}&#10;x+100=\boxed{y}\\&#10;0.8x+10=0.7y\\&#10;----------\\&#10;0.8x+10=0.7\left( \boxed{x+100} \right)&#10;\end{cases}&#10;\\\\\\&#10;0.8x+10=0.7x+70\implies 0.8x-0.7x=70-10\implies 0.1x=60&#10;\\\\\\&#10;x=\cfrac{60}{0.1}\implies x=600
6 0
3 years ago
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