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gayaneshka [121]
3 years ago
7

Rena, Chris, and John sent a total of 100 and one text messages during the weekend. Chris sent five more messages than Reina. Jo

hn sent two times as many messages as Rena. How many messages did they each send?
Mathematics
1 answer:
timurjin [86]3 years ago
7 0

Answer:

Reina sent 24

Chris sent 29

John sent 48

Step-by-step explanation:

Reina sent 24.

Chris sent 5 more

So 29.

John sent double if Reina's.

24•2

48

Then add to check work.

24+29+48

101

Hope this helps

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In the first week of August, there were 1,060 people at an amusement
Marrrta [24]

<u>Answer:</u>

In second week there is percentage decrease (-ve sign) of 20% in people visiting compare to first week.

In third week there is percentage increase of 50% in people visiting compare to second week.

In fourth week there is percentage decrease of 75% in people visiting compare to third week.

<u>Solution:</u>

Need to determine percentage change in the number of people who went to amusement park for each week in august.

Given that,

In first week of august number of people went to amusement park let say p_1 = 1060

In second week of august number of people went to amusement park let say p_2 = 848

In third week of august number of people went to amusement park let say p_3 = 1272

And in fourth week of august number of people went to amusement park let say p_4 = 318

<u><em>Percentage change from first week to second week is as follows</em></u>

\% \text { change }=\frac{p_{2}-p_{1}}{p_{1}} \times 100=\frac{848-1060}{1060} \times 100

=\frac{-212}{1060} \times 100=-20 \%

So in second week there is percentage decrease (-ve sigh) of 20% in people visiting compare to first week.

<u><em>Percentage change from second week to third week is as follows </em></u>

\begin{aligned} \% \text { change }=\frac{p_{3}-p_{2}}{p_{2}} \times 100 &=\frac{1272-848}{848} \times 100 =\frac{424}{848} \times 100=50 \% \end{aligned}

So in third week there is percentage increase of 50% in people visiting compare to second week

<u><em>Percentage change from third week to fourth week is as follows </em></u>

\begin{aligned} \% \text { change }=& \frac{p_{4}-p_{3}}{p_{3}} \times 100=\frac{318-1272}{1272} \times 100 =\frac{-954}{1272} \times 100=-75 \% \end{aligned}

So in fourth week there is percentage decrease of 75% in people visiting compare to third week

5 0
4 years ago
Trent told his friends it would take him 90 minutes to mow the lawn. It only took him
marta [7]

Answer:

The answer is 16%

Step-by-step explanation:

use the percent error formula.

\frac{|E-T|}{|T|} *100

in this problem,

e= 75

t=90

substitute and solve.

\frac{|75-90|}{|90|} *100\\\frac{|-15|}{|90|}*100\\\\ .16667*100\\

16%

we are dealing with percents so rounding to nearest whole number will suffice.

hope this helps!

7 0
4 years ago
Evaluate 6(8 – 3 <br><br> its for Algebra 1
Aleks [24]
You would get 48-18=30
8 0
4 years ago
What is the solution of the system of equations shown in the graph?
Rudiy27

Answer:

The solution of the system of equations shown in the graph is (2,0)

Step-by-step explanation:

It's easy

You just look for the point of intersections the lines make.

The point is on the number 2  on the x axis, and number 0 on the y axis. Therefore its (2,0).

Happy to help!

3 0
3 years ago
I need help with 6 and 7 please
PolarNik [594]
For number 6 its A. 4
For number 7 its B. -2/5
7 0
3 years ago
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