F(x)=2x-5
k(x)=f(x+3)=2(x+3)-5=2x+6-5=2x+1
k(x)=2x+1
Answer:
Quadrant I: (1,1), (4,3)
Quadrant II: (-2, 3), (-1, 1)
Step-by-step explanation:
Quadrant I points have positive x and y values. Quandrant II points have negative x values and positive y values.
Answer:
The ans is correct. But I think C is also correct.
Step-by-step explanation:
The vector equation of the line through the origin perpendicular to the plane is
.. (x, y, z) = t(2, 3, -1)
so the point of interest will satisfy
.. 2(2t) +3(3t) -(-t) = -3
.. 14t = -3
.. t = -3/14
and its coordinates are (x, y, z) = (-3/7, -9/14, 3/14)
