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gtnhenbr [62]
3 years ago
7

PLZ QUICKLY SOMEONE ANSWER the question is find value of a​

Mathematics
1 answer:
klasskru [66]3 years ago
4 0
Angle p equals 90 degrees so angle a equals 180-90-41=49
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2. At Fly-Right Airlines, passengers are informed that checked bags must weigh 40 lb or less, or they will have to pay a fee for
Ilya [14]

Answer:

see below

Step-by-step explanation:

a)  w <= 40 lbs

b)  Do you have any bag that weigh 0 lbs or negative lbs?

We need to rewrite the inequality so that these are not there

0<= w <= 40 lbs

6 0
3 years ago
3. Find the slope of the line that passes through the pair of points.<br> (0, 0), (3,5)
Katena32 [7]

Answer:

5/3

Step-by-step explanation:

5 0
3 years ago
Find the value of w<br> A. 141<br> B. 110<br> C. 80<br> D. 100
saw5 [17]

Answer:

141

Step-by-step explanation:

Angle Formed by Two Chords= 1/2(SUM of Intercepted Arcs)

We know z+70 = 180 since they form a straight line

z = 110

z = 1/2 ( 79+w)

110 = 1/2 ( 79+w)

220 = 79+w

220-79 = w

141 =w

5 0
2 years ago
Caroline has $25 to spend on the school field trip after paying $13.00 for the cost pf the field trip and $6.25 for lunch how mu
Alex787 [66]

Answer:

Caroline has $5.75 left

Step-by-step explanation:

$25 - Caroline's money

$13 - field trip

$6.25 - lunch

$25 - ($13 + $6.25)

$25 - $19.25

= $5.75

4 0
3 years ago
Consider a population of Pacific tree frogs (Pseudacris regilla). In this population of frogs, a single locus controls the produ
zloy xaker [14]

Answer:

Step-by-step explanation:

Hello!

Use these data to calculate the chi-square statistic. Report your calculated chi-square statistic to two decimal places.

In this example, the study variable is X: genotype of a single locus two allele gene that codes the mating call of tree frogs. Categorized: S₁S₁, S₁S₂, and S₂S₂.

Usually, when you have a sample of observed genotypes of a gene of interest, the goal is to check if these genotypes follow a theoretical model such as the frequency models proposed by Mendel.

In Mendelian genetics, when two heterozygous individuals (Aa, Aa) from the F1 generation are crossed, you expect the next generation (F2) to show the genotypic ratio 1:2:1 ⇒ This model means that out of 4 descendants 1 will have the genotype AA, 2 will have the genotype Aa and 1 will have the genotype aa. Since there is no theoretical model specified I'll use the mendelian ratio 1:2:1.

If this theory applies to the population then we'll expect that the proportion of the first genotype is P(S₁S₁)= 0.25, the second P(S₁S₂)= 0.5 and the third P(S₂S₂)=0.25

To test if the observed genotypes follow the theoretical model you have to apply a Chi-Square Goodness of Fit Test.

For this test the hypotheses are:

H₀:P(S₁S₁)= 0.25; P(S₁S₂)= 0.5; P(S₂S₂)=0.25

H₁: The data is not consistent with the specified distribution.

α: 0.05

Statistic: X^2= sum(\frac{(o_i-e_i)^2}{e_i} )~X^2_{k-1}

Where:

oi: Observed frequency for the i- category

ei: Expected frequency for the i-category

k= number of categories

The rejection region for this test is one-tailed to the right. This is so because if the observed and expected values are too different (the chi-square value will be high) this will mean that the population doesn't follow the theoretical model and thus reject the null hypothesis. If the differences between what's observed and what's expected are small, this will mean that the population follows the theoretical model (and you'll obtain a small chi-square value) and you will not reject the null hypothesis.

The critical value is:

X^2_{k-1; 1 - \alpha }= X^2_{3;0.95}= 7.815

If the statistic is at least 7.815, the decision is to reject the null hypothesis.

If the statistic is less than 7.815, the decision is to not reject the null hypothesis.

Step 1 is to obtain the expected frequencies for each category:

e_i= n*P_i

e_{S_1S_1}= n * P(S_1S_1)= 1341*0.25= 335.25

e_{S_1S_2}= n * P(S_1S_2)= 1341 * 0.5= 670.5

e_{S_2S_2}= n * P(S_2S_2)= 1341*0.25= 335.25

Note: the summatory of the expected frequencies is equal to the total of observations ∑ei= n. If you have doubts about your calculations, you can add them to check it: ∑ei= 335.25 + 670.5 + 335.25= 1341

X^2= (\frac{(987-335.25)^2}{335.25} )+(\frac{(333-670.5)^2}{670.5} )+(\frac{(21-335.25)^2}{335.25} ) = 1731.50

Decision: Reject null hypothesis.

I hope this helps!

3 0
3 years ago
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