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3 years ago

75g of flour and 135 ml of milk are used to make 12 biscuits. How much flour is needed to make 30 biscuits?

1 answer:

3 0

The answer is 187 1/2 cups. You have to divide 75 by 12 to get how much flour is in 1 biscuit and you multiply that by 30

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1. round 24,061,562 to the nearest 1,000 and 100,000

Arlecino [84]

24,102,000 is the answer

5 0

3 years ago

Evaluate F(1)

KonstantinChe [14]

ANSWER

B. 1

EXPLANATION

The given function is

$f(x) =\left \{ {{x^{2} +3 (if) -5 \leq x< 1} \atop {x (if) 1 \leq x \leq 5 }} \right.$

This is a piece-wise defined function.

We want to find f(1)

We substitute x=1 into f(x)=x because, 1 belongs to the interval,

1≤x≤5

f(1)=1

The correct answer is B.

8 0

3 years ago

8(a+b) when a is 5 and b is 3

lidiya [134]

Substitute 5 and 3 for a and b in the original expression.

8(a+b)

8(5+3)

Using the rules of PEMDAS, solve the inside of the parentheses first, then multiply accordingly.

8(8)

<u>The final answer is 64.</u>

4 0

4 years ago

What is the value of W if A equals 184 cm² and I equals 23 cm

dimulka [17.4K]

184 / 23 = 8
so it would be 8

5 0

4 years ago

In Mary's first math test she scored 87%. The mean and standard deviation for the class were 71% and 18% respectively. In her se

erica [24]

Answer:

Step-by-step explanation:

Since your population are the students in math class, you can use the z-score formula $z=(x-\mu)/\sigma$ in order to comparing the two math test scores. Where $\mu$ is the mean for the class, $\sigma$ is the standars deviation and x is Mary score.

For the first test $\mu=.71 , \sigma=.18,x=.87$ , so , $z_{1} = (.87-.71)/(.18)=.88$ .

For the second test $\mu=.53 , \sigma=.14,x=.66$ , so , $z_{1} = (.66-.53)/(.14)=.93$

Mary do better in the second test, relative to the rest of the class (because $.88 \leq .93$ , it means the second score is nearer to the mean score of the class than the first one )

6 0

4 years ago