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Phantasy [73]
3 years ago
12

PLEASEEE I NEED HELP

Mathematics
1 answer:
Verizon [17]3 years ago
6 0
Y=(x+4)^2-25 , (4,-25)
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Draw the image of the following segment after a dilation centered at the origin with a scale factor of 2/3
stepladder [879]

Answer:

When we have a point (a, b) and we have a dilation of scale factor K centered at the origin, the new coordinates of this point will be:

(K*a, K*b)

In this case, we can find the original coordinates of the endpoints of the original segment.

Then apply the dilation to these points, and then draw a new segment whose endpoints are the dilated points.

The endpoints of the original segment are (i can not see the image very well, so i may be wrong when noticing the points).

The first endpoint is (6, 9) and (12, 12)

Now we apply a dilation with a scale factor K = 2/3.

then we get the points:

((2/3)*6, (2/3)*9) = (4, 6)

and the other point is:

((2/3)*12, (2/3)*12) = (8, 8)

Now we need to draw a segment whose endpoints are (4, 6) and (8, 8)

The segment can be seen in the graph below.

3 0
3 years ago
X/2 this math is hard for me plz help
Anuta_ua [19.1K]

Answer:

45.67(2)

Step-by-step explanation:

ye

3 0
3 years ago
Read 2 more answers
How many numbers between 1 and 1000 do not contain the digits 8, and 9 ?
sammy [17]

Answer:

998

Step-by-step explanation:

I haven't included the <em><u>1</u></em> or the <em><u>1000</u></em>

6 0
4 years ago
Read 2 more answers
Express your answer in simplest a+ bi form. (8+5i)(3+2i)-(4+i)(4-i)
Elanso [62]

\qquad\qquad\huge\underline{{\sf Answer}}

Let's solve ~

\qquad \sf  \dashrightarrow \:(8 + 5i)(3 + 2i) - (4 + i)(4 - i)

\qquad \sf  \dashrightarrow \:[( 8 \sdot3) + (8 \sdot2i) + (5i \sdot3) + (5i \sdot2i)] -[( 4 \sdot4) + (4 \sdot - i) + (i \sdot4) + (i \sdot - i)]

\qquad \sf  \dashrightarrow \:[24+ 16i + 15i+ 10i {}^{2} ] -[16 - 4 i+ 4i - i {}^{2} ]

\qquad \sf  \dashrightarrow \:[24+ 31i+ 10 {}{( - 1)} ] -[16 - ( - 1){}^{} ]

\qquad \sf  \dashrightarrow \:[24+ 31i - 10 {}{} ] -[16  + 1{}^{} ]

\qquad \sf  \dashrightarrow \:[14+ 31i {}{} ] -[17{}^{} ]

\qquad \sf  \dashrightarrow \: - 3+ 31i {}{}

I hope you understood the procedure ~

5 0
2 years ago
A couple of students are testing a prototype for a science project on rockets. They launch the rocket and record its height over
Illusion [34]
For this case we have the following table:
 x    f(x)
 <span><span><span>0     2
 </span><span>1     5
 </span><span>2    10
 </span><span>3     17
</span></span></span> The equation that best fits the data in the table, for this case, is given by a quadratic function.
<span><span><span> </span></span></span>The quadratic function in its standard form is:
 f (x) = x2 + 2x + 2
 Answer:
 f (x) = x2 + 2x + 2
8 0
3 years ago
Read 2 more answers
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