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ozzi
1 year ago
6

2 cubed x what x 5 = 120 please i really need help

Mathematics
2 answers:
marin [14]1 year ago
5 0

Answer:

2x3x5=120

Step-by-step explanation:

nevsk [136]1 year ago
4 0

Answer:

30 is the missing number.

Step-by-step explanation:

The equation is,

→ 2³ × x × 5 = 120

Then the value of x will be,

→ 2³ × x × 5 = 120

→ 8 × x × 5 = 120

→ x × 40 = 120

→ x = 120/40

→ [ x = 30 ]

Hence, the value of x is 30.

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Find the area of the shaded region ​
o-na [289]

so hmmm let's get the area of the whole hexagon, and then get the area of the circle inside it, then <u>subtract the area of the circle from that of the hexagon's</u>, what's leftover is what we didn't subtract, namely the shaded part.

\textit{area of a regular polygon}\\\\ A=\cfrac{1}{4}ns^2\cot\stackrel{\stackrel{degrees}{\downarrow }}{\left( \frac{180}{n} \right)}~ \begin{cases} n=\textit{number of sides}\\ s=\textit{length of a side}\\[-0.5em] \hrulefill\\ n=\stackrel{hexagon}{6}\\ s=\frac{9}{2} \end{cases}\implies A=\cfrac{1}{4}(6)\left( \cfrac{9}{2} \right)^2 \cot\left( \cfrac{180}{6} \right)

A=\cfrac{1}{4}(6)\cfrac{9^2}{2^2} \cot(30^o)\implies A=\cfrac{243}{8}\cot(30^o)\implies A=\cfrac{243\sqrt{3}}{8} \\\\[-0.35em] ~\dotfill\\\\ \textit{area of circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=\frac{4}{5} \end{cases}\implies A=\pi \left( \cfrac{4}{5} \right)^2\implies A=\cfrac{16\pi }{25} \\\\[-0.35em] ~\dotfill

\stackrel{\textit{area of the hexagon}}{\cfrac{243\sqrt{3}}{8}}~~ - ~~\stackrel{\textit{area of the circle}}{\cfrac{16\pi }{25}}\implies \cfrac{6075\sqrt{3}-128\pi }{200}

5 0
2 years ago
Pleaseee CAN SOMEONE HELP ME ITH THISS:(
laiz [17]

Answer:

Option 3

Step-by-step explanation:

When it says 12 less, that means -12.

Hope I helped. :)

4 0
3 years ago
Can someone help and give me a step by step explanation please?!
vitfil [10]

9514 1404 393

Answer:

  • ∠QSR = 78°
  • ∠SQR = 51°

Step-by-step explanation:

The measure of an inscribed angle (QTR) is half the measure of the arc it intercepts. The measure of an arc is the same as the measure of the central angle it intercepts. So, we have ...

  ∠QSR = 2×∠QTR

  ∠QSR = 2×39°

  ∠QSR = 78°

__

Sides SQ and SR are radii of circle S, so are the same length. That means triangle QRS is an isosceles triangle and the base angles SQR and SRQ are congruent. The sum of angles in a triangle is 180°, so we have ...

  ∠QSR + 2(∠SQR) = 180°

  78° + 2(∠SQR) = 180° . . . . fill in the value we know

  2(∠SQR) = 102° . . . . . . . . . subtract 78°

  ∠SQR = 51° . . . . . . . . . . . . .divide by 2

7 0
2 years ago
After releasing of radioactive material into.The atnosphere from.A nuclear.Powe plant in a country in 1988, the hay in that coun
Radda [10]

Answer:

the question is incomplete, so I looked for a similar one:

<em>After the release of radioactive material into the atmosphere  from a nuclear power plant, the hay was contaminated by iodine  131 ( half-life, 8 days). If it is all right to feed the hay to cows  when 10% of the iodine 131 remains, how long did the farmers  need to wait to use this hay? </em>

iodine's half life (we are given x, we need to find b):

0.5A₀ = A₀eᵇˣ

x = 8 days

we eliminate A₀ from both sides

0.5 = eᵇ⁸

ln 0.5 = ln eᵇ⁸

-0.69315 = b8

b = -0.69315 / 8 = -0.08664

since the farmers need to wait until only 10% of the iodine remains (we already calculated b, now we need to find x):

0.1A₀ = A₀eᵇˣ

0.1 = eᵇˣ

ln 0.1 = bx

where b = -0.08664

x = ln 0.1 / -0.08664  = -2.302585 / -0.08664  = 26.58 days

4 0
3 years ago
There are 3,072 books in the school library. There are 96 sixth graders. If the sixth graders teamed up to read all the books, h
Semenov [28]
The only thing you should do is to divide 3,072 by 96 and the answer is 32.
So each of them should read 32 books :)))
I hope this is helpful
have a nice day
7 0
3 years ago
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