What you want to do is take one of the 2 equations and isolate one variable. you will then use the value that you find for the variable and plug it back into the other equation. here is how:
This would be easiest to do with the second equation in the set since the x is not being multiplied by anything. So lets isolate the x in the second equation.
add 0.9y to both sides and you get:
x=4.5+0.9y
we now know what x is equal to in terms of y. so lets replace the x in the first equation with the new value. You get:
1.5(4.5+0.9y)-1.9y=-29
Now just solve for y:
6.75+1.35y-1.9y=-29
1.35y-1.9y=-35.75
-0.55y=-35.75
y=65
so now you know that y=65 so plug 65 in as y in the second equation to find x
x-0.9*65=4.5
Now simply solve for x
x-(-58.5)=4.5
x+58.5=4.5
x=-54
Hope this helped! :)
You can get the app Air Math I have the app and it helps a lot
Answer:
1608.5 cm³
Step-by-step explanation:
Use the cylinder volume formula, V = 
r²h
If the diameter is 16 cm, then the radius is 8 cm.
Plug in the radius and height into the formula, and solve:
V = r²h
V = (8)²(8)
V = (64)(8)
V = 1608.5
So, to the nearest tenth, the volume of the cylinder is 1608.5 cm³
Answer:
A x = 3
Step-by-step explanation:
A = ½θR²
R = x
x = √(2Α/θ)
θ = (360 - 60)(π/180) = 5π/3 radians
x = √(2(15π/2) / (5π/3))
x = √(15π(3/5π))
x = √9
x = 3
