Which ordered pair is a solution of the equation 3x+4y>=20

How does claiming more allowances on a W-4 form affect the deductions on a paycheck?

tatiyna

More money..............

8 0

4 years ago

David invested 220 in a savings account that’s offers a 3% return on the investment the value of David’s investment will be at l

Levart [38]

Zzzzzzzzzzzzzzzzzzzzzzzzzzzzzz

5 0

3 years ago

Read 2 more answers

The following data points represents how many tunnels Gary the groundhog dug each year. 18,5,13,9,6,2,10 using the data to creat

aleksandr82 [10.1K]

Answer:

The histogram for the data is attached below.

Step-by-step explanation:

The methods commonly used for depicting a frequency distribution are:

Histogram/Column graph
Bar graph
Frequency Polygon
Pie chart

Out of these, one of the most general and extensively used devices of illustrating a frequency distribution is the histogram.

The data provided for the number of tunnels Gary the groundhog dug each year is:

S = {18, 5, 13, 9, 6, 2, 10}

The histogram for the data is attached below.

5 0

4 years ago

Please help help help help help help

nevsk [136]

Answer:

y is equal to (-1/4)x

hope this helped! :)

7 0

3 years ago

when 6 is subtracted from the square of a number, the result is 5 times the number. Find the negative solution.

sveta [45]

When 6 is subtracted from the square of a number, the result is 5 times the number, then the negative solution is -1

<h3><u>Solution:</u></h3>

Given that when 6 is subtracted from the square of a number, the result is 5 times the number

To find: negative solution

Let "a" be the unknown number

Let us analyse the given sentence

square of a number = $a^2$

6 is subtracted from the square of a number = $a^2 - 6$

5 times the number = $5 \times a$

<em><u>So we can frame a equation as:</u></em>

6 is subtracted from the square of a number = 5 times the number

$a^2 - 6 = 5 \times a\\\\a^2 -6 -5a = 0\\\\a^2 -5a -6 = 0$

<em><u>Let us solve the above quadratic equation</u></em>

For a quadratic equation $ax^2 + bx + c = 0$ where $a \neq 0$

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here in this problem,

$a^2-5 a-6=0 \text { we have } a=1 \text { and } b=-5 \text { and } c=-6$

Substituting the values in above quadratic formula, we get

$\begin{array}{l}{a=\frac{-(-5) \pm \sqrt{(-5)^{2}-4(1)(-6)}}{2 \times 1}} \\\\ {a=\frac{5 \pm \sqrt{25+16}}{2}=\frac{5 \pm \sqrt{49}}{2}} \\\\ {a=\frac{5 \pm 7}{2}}\end{array}$

We have two solutions for "a"

$\begin{array}{l}{a=\frac{5+7}{2} \text { and } a=\frac{5-7}{2}} \\\\ {a=\frac{12}{2} \text { and } a=\frac{-2}{2}}\end{array}$

We have asked negative solution. So a = -1

Thus the negative solution is -1

6 0

3 years ago