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vagabundo [1.1K]
3 years ago
13

Pls help me i will give u brainliest!

Mathematics
1 answer:
Tema [17]3 years ago
5 0

Answer: im almost positive its -1 1/2

Step-by-step explanation:

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Function 1: y = 4x + 5
rosijanka [135]

Answer:

Option B is correct

Function 1, because the slope is 4 and the slope of function 2 is 2.

Step-by-step explanation:

Slope-intercept form:

The equation of line is given by:

y=mx+b

where, m is the slope and b is the y-intercept

As per the statement:

Function 1: y = 4x + 5

On comparing with [1] we have;

Slope of function 1  = 4

Function 2: The line passing through the points (1, 6) and (3, 10).

Using slope formula:

\text{Slope}= \frac{y_2-y_1}{x_2-x_1}

Substitute the given points we have;

\text{Slope}= \frac{10-6}{3-1}

⇒\text{Slope}= \frac{4}{2}

Simplify:

⇒\text{Slope}=2

⇒\text{Slope}= \frac{4}{2}

⇒ Slope of the function 2 is, 2

Since, function 1 is greater rate of change.( i.e 4 > 2)

Therefore,

Function 1  has the greater rate of change,  because the slope is 4 and the slope of function 2 is 2.

3 0
3 years ago
Read 2 more answers
PLSS HELP ASAP TYSM <33 SORRY I COULDN'T FIND SCIENCE LOLL ​
dimaraw [331]

Answer:

Rock D.

Step-by-step explanation:

We can assume that the force that the catapult does is always the same.

So, here we need to remember Newton's second law:

F = m*a

force equals mass times acceleration.

Where acceleration is the rate of change of the velocity.

So, if we want the rock to hit closer to the catapult, the rock must be less accelerated than rock B.

So, we can rewrite:

a = F/m

So, as larger is the mass of the rock, smaller will be the acceleration of the rock after it leaves the catapult (because the mass is in the denominator). So if we want to have a smaller acceleration, we need to choose a rock with a larger mass than rock B.

Assuming that the mass depends on the size, the only one that has a mass larger than rock B is rock D.

So we can assume that rock D is the correct option.

5 0
3 years ago
What is the value of x in the diagram below? If necessary, round your answer
dolphi86 [110]
The answer might be c
3 0
3 years ago
Read 2 more answers
A special liquid is held in a tank described as (x 2 + y 2 ) ≤ z ≤ 1 in a Cartesian coordinate system. Assume that the density o
vivado [14]

Since \rho=\dfrac mV (density = mass/volume), we can get the mass/weight of the liquid by integrating the density \rho(x,y,z) over the interior of the tank. This is done with the integral

\displaystyle\int_{-1}^1\int_{-\sqrt{1-x^2}}^{\sqrt{1-x^2}}\int_{x^2+y^2}^1(2-z^2)\,\mathrm dz\,\mathrm dy\,\mathrm dx

which is more readily computed in cylindrical coordinates as

\displaystyle\int_0^{2\pi}\int_0^1\int_{r^2}^1(2-z^2)r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta=\boxed{\frac{3\pi}4}

7 0
3 years ago
(9, 8) is the midpoint of mc136-1.jpg. The coordinates of S are (10, 10). What are the coordinates of R?
kolbaska11 [484]
I cant see the image...but I take it that the midpoint is (9,8) and the endpoint S is (10,10) and ur looking for the other endpoint R.

midpoint formula : (x1 + x2) / 2, (y1 + y2) / 2
(10,10)....x1 = 10 and y1 = 10
(x,y)....x2 = x and y2 = y
so we sub
(10 + x) / 2, (10 + y) / 2 = 9/8

(10 + x) / 2 = 9
10 + x = 9 * 2
10 + x = 18
x = 18 - 10
x = 8

(10 + y) / 2 = 8
10 + y = 8 * 2
10 + y = 16
y = 16 - 10
y = 6

so endpoint R has coordinates of (8,6) <===
7 0
3 years ago
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