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Butoxors [25]
3 years ago
12

Ali bought a music system for rs 6375.00 and spent rs 75.00 on transportation . He sold it for 6400.00 . Find his profit or loss

percent
Mathematics
1 answer:
pentagon [3]3 years ago
6 0

Answer: Loss percent = 0.775%

Step-by-step explanation:

Here,

Total cost = Purchasing price + transportation

⇒ Total cost = 6375 + 75

⇒ Total cost = $ 6450

Selling price = $ 6400

Total cost > Selling price, hence it is a loss.

Loss percent formula :

Loss\% =\dfrac{\text{Loss}}{Total\ cost}\times100\\\\=\dfrac{Total\ cost - Selling price}{Total \ cost}\times100\\\\=\dfrac{6450-6400}{6450}\times100\\\\=\dfrac{50}{6450}\times100=0.775\%

Hence, Loss percent = 0.775%

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Archy [21]

Answer:

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Step-by-step explanation:

6 0
3 years ago
the sides of a square are increased by a scale factor of 7. The perimeter of the smaller square is 16 ft. What is the perimeter
avanturin [10]
The perimeter of the larger square is 112
3 0
3 years ago
Plz answer this asap first answer gets brainliest
Korvikt [17]

Answer:

g(x) has the greater max:  11 versus 6

Step-by-step explanation:

One can readily discern the max value of the graph; it is 6 and occurs at x =1.

Regarding the function g(x) = (-1/2)x^2 + 4x + 3:  Find the vertex, which also represents the max value:

Here the coefficients are a = -1/2, b = 4 and c = 3, so that the axis of symmetry is:

x = -b/(2a), which here is   x = -4 / ( 2·[-1/2] ) = -4 / (-1) = 4

At x = 4, the function (y) value is

g(4) = (-1/2)(4)² + 4(4) + 3, or

g(4) =    -8  +   16 + 3, or 11

This is greater than the max value of the graphed function.

8 0
4 years ago
Suppose that the lifetime of tv tubes are normally distributed with a standard deviation of 1.1 years. Suppose that exactly 20%
IrinaK [193]

Answer:

4.924 years

Step-by-step explanation:

Lets denote X the lifetime of a tv tube (In years). X has distribution N(\mu, 1.1) , with \mu unknown.

We know that P(X < 4) = 0.2. Using this data, we can find the value of \mu throught standarization.

Lets call Z = \frac{X - \mu}{1.1} the standarization of X. Z has distribution N(0,1), and its cummulative function, \phi is tabulated. The values of \phi can be found in the attached file.

P(X < 4) = P(\frac{X - \mu}{1.1} < \frac{4 - \mu}{1.1}) = P(Z < \frac{4 - \mu}{1.1}) = \phi(\frac{4 - \mu}{1.1}) = 0.2

The value q such that \phi (q) = 0.2 doesnt appear on the table. We can find it by using the symmetry of the normal density function. The opposite of q, -q must verify that \phi(-q) = 0.8 , hence -q must be equal to 0.84. Thus, q = -0.84

But this value of q should match with the number \frac{4 - \mu}{1.1} , so we have

\frac{4- \mu}{1.1} = -0.84

4 - \mu = 1.1 * (-0.84) = -0.924

\mu = 4 - (-0.924) = 4.924

Thus, the expected lifetime of TV tubes is 4.924 years.

I hope this works for you!

Download pdf
7 0
4 years ago
The number of arrivals per minute at a bank located in the central business district of a large city was recorded over a period
Sergio [31]

Answer:

a. μ = 25

b. σ = 16.496

Step-by-step explanation:

Note: See the attached excel for the calculation of Mean and Deviation from Mean.

Let: N = Number of observation = 9

F = Frequency

Therefore, we have:

a. Compute the expected number of arrivals per minute. μ=___( please type as an integer or a decimal)

From the attached excel file, we have:

Total F = 200

Therefore, we have:

μ = Mean = Total of F / (N - 1) = 200 / (9 - 1) = 25

b. Compute the standard deviation σ=___(please round to three decimal places as needed)

From the attached excel file, we have:

Total (F -  μ)^2 = 2,177

σ = Standard deviation = (Total of (F -  μ)^2 / (N - 1))^0.5 = (2,177 / (9 - 1))^0.5 = 16.496

Download xlsx
7 0
3 years ago
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