Mi padre compró un radio por cierta suma de dinero, un televisor que costó 10 veces más que el radio y un reproductor cuyo preci
o es 80$ menos que el televisor, ¿Cuánto costó cada aparato siento tal mi padre gastó 850$?
1 answer:
Answer:
For radio = $40.43
Television = $444.73
Player = $364.73
Step-by-step explanation:
The computation of the each device cost is shown below:
let us assume the following things
radio be x
television x + 10x
player x + 10x - $80
Now the equation is
x + x + 10x + x + 10x - $80 = $850
3x + 20x - $80 = $850
23x = $930
x = $40.43
For radio = $40.43
Television = $40.43 + 10(40.43)
= $40.43 + $404.3
= $444.73
and, the player would be
= $444.73 - $80
= $364.73
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nagwa
mthway
The answer would be $2.70
Here are the answers to problem 1..
a) 11
b) 5/36
c) 25 Times because 7 has a probability of 16.667%
d) 25 Times because 10, 11, and 12 have a probability sum of 16.667% ironically...
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4/(6+89-34-89+190)
=4/162
=2/81
That's your answer.