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3 years ago

Plssss helppppp I need this for my homework

Mathematics

2 answers:

Fed [463]3 years ago

7 0

Answer:

First divide the 1 and 5 then 4 and 7 then 5 and 2

Studentka2010 [4]3 years ago

4 0

Answer:

The correct answer is,

$2 \frac{15}{28}$

I'm 100000000% sure.

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HW-02 Problem No.2.1 / 10 pas 5x1 - x2 = 1 ( 3x2 - 2x1 = -3 Solve the system of linear equations by modifying it to REF and to R

IrinaVladis [17]

Answer:

$REF= \left[\begin{array}{ccc}5&-1&1\\0&\frac{-7}{5} &\frac{-18}{5}\end{array}\right]$

$RREF=\left[\begin{array}{ccc}1&0&\frac{5}{7} \\0&1&\frac{18}{7}\end{array}\right]$

Step-by-step explanation:

The augmented matrix of the system is: $\left[\begin{array}{ccc}5&-1&1\\3&-2&-3\end{array}\right]$

First we find the stepped form of A (REF):

1. We subtract 3/5 from row 1 to row 2 (R2- $\frac{3}{5}$ R1) and get the matrix

$\left[\begin{array}{ccc}5&-1&1\\0&\frac{-7}{5} &\frac{-18}{5}\end{array}\right]$

Note that this matrix is in echelon form.

Now we find the reduced row echelon form of the augmented matrix (RREF)

2. From the previous matrix, we multiply the first row by 1/5 and the second row by -5/7 and obtain the matrix:

$\left[\begin{array}{ccc}1&\frac{-1}{5} &\frac{1}{5} \\0&1&\frac{18}{7}\end{array}\right]$

3. From the previous matrix, to row 1 we add 1/5 of row 2 (R1 + $\frac{1}{5}$ R2) and we obtain the matrix

$\left[\begin{array}{ccc}1&0&\frac{5}{7} \\0&1&\frac{18}{7}\end{array}\right]$

which is the reduced row echelon form of the augmented matrix.

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3 years ago