Consider the digit expansion of one of the numbers, say,
676₉ = 600₉ + 70₉ + 6₉
then distribute 874₉ over this sum.
874₉ • 6₉ = (8•6)(7•6)(4•6)₉ = (48)(42)(24)₉
• 48 = 45 + 3 = 5•9¹ + 3•9⁰ = 53₉
• 42 = 36 + 6 = 4•9¹ + 6•9⁰ = 46₉
• 24 = 18 + 6 = 2•9¹ + 6•9⁰ = 26₉
874₉ • 6₉ = 5(3 + 4)(6 + 2)6₉ = 5786₉
874₉ • 70₉ = (8•7)(7•7)(4•7)0₉ = (56)(49)(28)0₉
• 56 = 54 + 2 = 6•9¹ + 2•9⁰ = 62₉
• 49 = 45 + 4 = 5•9¹ + 4•9⁰ = 54₉
• 28 = 27 + 1 = 3•9¹ + 1•9⁰ = 31₉
874₉ • 70₉ = 6(2 + 5)(4 + 3)10₉ = 67710₉
874₉ • 600₉ = (874•6)00₉ = 578600₉
Then
874₉ • 676₉ = 578600₉ + 67710₉ + 5786₉
= 5(7 + 6)(8 + 7 + 5)(6 + 7 + 7)(0 + 1 + 8)(0 + 0 + 6)₉
= 5(13)(20)(20)(1•9)6₉
= 5(13)(20)(20 + 1)06₉
= 5(13)(20)(2•9 + 3)06₉
= 5(13)(20 + 2)306₉
= 5(13)(2•9 + 4)306₉
= 5(13 + 2)4306₉
= 5(1•9 + 6)4306₉
= (5 + 1)64306₉
= 664306₉
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6(x-2.5) ≥ 8-6(3.5+x)
A number is before a parenthesis. The first step is to multiply.
6(x-2.5) = 6x -15
8-6(3.5+x)
2(3.5+x)= 7+2x
6x-15≥7+2x
Now solve
6x-15≥7+2x
-2x -2x
(-2x+2x)= They cancel out
(6x-2x)= 4x
4x-15≥7
+15 +15
4x≥22
/4 /4
You get= x≥5.5
Answer:
There is 1 possible combination
Step-by-step explanation:
There are 5 assignments and they must be completed. 5. We want to find the number of combinations, then we use the formula of combinations.
Where n is the total number of objects and you choose r from them
Then
Thank you for posting your question here at brainly. I will assume that the equation is that <span>13,094 + 259,728. Below is the solution:
</span>13,094 + 259,728 = 272,822
Sum is t<span>he total amount resulting from the addition of two or more numbers, amounts, or items.</span>
