Question

Katharine has a bag containing 20 dried beans. Eight of the beans are painted blue. If Katharine selects a bean from the bag at random, what is the probability that she will draw a bean that is NOT blue? Al out of 3 B 2 out of 5 C 3 out of 5 D 2 out of 3
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Answer 1

Given:

Total number of beans = 20

Number of blue of beans = 8

One bean is selected from the bag at random.

To find:

The probability that she will draw a bean that is NOT blue.

Solution:

We have,

Total number of beans = 20

Number of blue of beans = 8

Number of non-blue beans = 20 - 8

                                              = 12

Now, the probability that she will draw a bean that is NOT blue is

$P(\text{Bean is not blue})=\dfrac{\text{Number of non-blue beans}}{\text{Total number of beans}}$

$P(\text{Bean is not blue})=\dfrac{12}{20}$

$P(\text{Bean is not blue})=\dfrac{3}{5}$

Therefore, the correct option is C.