# [4-5{1-(4-3+1)}] of 100% equals a) 50% b)-1% c)zero d)100%

Mathematics

1 answer:

Nikitich [7]1 year ago

7 0

Answer:

To solve this, we need to first evaluate the given expression. We can do that by simplifying the contents of each bracket, starting with the innermost one:

[4-5{1-(4-3+1)}]

⇒ [4 - 5{1 - (2)}]

⇒ [4 - 5{-1}]

⇒ 4 - (-5)

⇒ 4 + 5

⇒ 9

Now we can calculate what 9 out of 100 is:

9 of 100 = $\frac{9}{100}$

⇒ 9%

You might be interested in

6.X + 4 using the algebra

Tems11 [23]

Answer:

Step-by-step explanation:

coooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooool

5 0

2 years ago

Read 2 more answers

Consider the function below. f(x)= x^3 + 2x^2 - x - 2 plot the x and y intercepts of the function

dimulka [17.4K]

In the Figure below is shown the graph of this function. We have the following function:

$f(x)=x^3+2x^2-x-2$

The $y-intercept$ occurs when $x=0$ , so:

$f(0)=(0)^3+2(0)^2-(0)-2=-2$

Therefore, the $y-intercept$ is the given by the point:

$\boxed{(0,-2)}$

From the figure we have three $x-intercepts$ :

$\boxed{P_{1}(-2,0)} \\ \boxed{P_{2}(-1,0)} \\ \boxed{P_{3}(1,0)}$

So, the $x-intercepts$ occur when $y=0$ . Thus, proving this:

$f(x)=x^3+2x^2-x-2 \\ \\ For \ P_{1}:\\ If \ x=-2, \ y=(-2)^3+2(-2)^2-(-2)-2=0 \\ \\ For \ P_{2}:\\ If \ x=-1, \ y=(-1)^3+2(-1)^2-(-1)-2=0 \\ \\ For \ P_{3}:\\ If \ x=1, \ y=(1)^3+2(1)^2-(1)-2=0$