complete question:
The sum of the digits of a two-digit numeral is 8. If the digits are reversed, the new number is 18 greater than the original number. How do you find the original numeral?
Answer:
The original number is 10a + b = 10 × 3 + 5 = 35
Step-by-step explanation:
Let
the number = ab
a occupies the tens place while b occupies the unit place. Therefore,
10a + b
The sum of the digits of two-digits numeral
a + b = 8..........(i)
If the digits are reversed. The reverse digit will be 10b + a. The new number is 18 greater than the original number.
Therefore,
10b + a = 18 + 10a + b
10b - b + a - 10a = 18
9b - 9a = 18
divide both sides by 9
b - a = 2...............(ii)
a + b = 8..........(i)
b - a = 2...............(ii)
b = 2 + a from equation (ii)
Insert the value of b in equation (i)
a + (2 + a) = 8
2a + 2 = 8
2a = 6
a = 6/2
a = 3
Insert the value of a in equation(ii)
b - 3 = 2
b = 2 + 3
b = 5
The original number is 10a + b = 10 × 3 + 5 = 35
Answer:
1 and 2/4 I think
Step-by-step explanation:
2 1/3 / 1 3/5 7/3 / 8/5 7/3 * 5/8 7*5 = 35 3*8 = 24 35 / 24 1 and 11/24 1 and 11/24 1 and 11/24
Hope this helps!
Answer:
In the pic
Step-by-step explanation:
If you have any questions about the way I solved it, don't hesitate to ask me in the comments below =)
Answer:
45 i think i dont know
Step-by-step explanation:
m
∠
2
=
x
holds true.
Complementary angles have a sum of
90
˚
. Thus, if
∠
1
and
∠
2
are complementary,
m
∠
1
+
m
∠
2
=
90
Substitute the equivalent forms of these angle measurements
(
x
,
x
)
.
x
+
x
=
90
Solve algebraically.
2
x
=
90
x
=
45
Each angle is
45
˚
.
