Answer:
⇒ The given quadratic equation is x2−kx+9=0, comparing it with ax2+bx+c=0
∴ We get, a=1b=−k,c=9
⇒ It is given that roots are real and distinct.
∴ b2−4ac>0
⇒ (−k)2−4(1)(9)>0
⇒ k2−36>0
⇒ k2>36
⇒ k>6 or k<−6
∴ We can see values of k given in question are correct.
Answer:
120
Step-by-step explanation:
15/1.5=10
10 x 12=120
Answer: correct answer is B.(2x+3y)(4x^2-6xy+9y^2)
8x^3 + 27y^3
(2x)^3+(3y)^3
(2x+3y)(4x^2-6xy+9y^2) <----answer
Answer/Step-by-step explanation:
✔️As a set of order pairs, the mapping can be represented as (x, y), where x = input and y = output.
Thus:
{(1, 6), (2, 6), (3, 6), (4, 8)}
✔️As a table we have input as x, and y as output, such as:
x | y
1 | 6
2 | 6
3 | 6
4 | 8
I don’t quite understand this question since it’s all spaced out and there’s no picture but since domain is x/the indecent variable, “x = -6, -1, 0, 3” (the first answer choice” is correct
