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Andre45 [30]
2 years ago
14

Please help Last Question!!!

Mathematics
1 answer:
pshichka [43]2 years ago
8 0

Answer:

  24%

Step-by-step explanation:

2610 of the 10730 students are graduates. The probability of choosing a graduate at random from all students is ...

  2610/10730 × 100% ≈ 24.324% ≈ 24%

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Giving brainliest !!!
Alona [7]
It is given that AB is parellel to CD. These two lines are cut by a transversal, creating angles BAC and DCA. Thus, angle BAC is congruent to angle DCA because alternate interior angles are congruent. It is also given that angle ACB is congruent to angle CAD. Therefore, triangle ABC is congruent to triangle CDA because of the ASA theorem.
4 0
3 years ago
A dog runs 100 meters in 30 seconds. How fast is he running
matrenka [14]

Answer:

3.33 m/s

Step-by-step explanation:

Distance divided by time = speed

100/30 = 3.33 m/s

6 0
2 years ago
What is 12/25 as a percent
mart [117]
12/25 is 48% becuase 12/25 is alao 48/100 because 12 x 4= 48 and 25 x 4= 100.
7 0
3 years ago
Read 2 more answers
Day care centers expose children to a wider variety of germs than the children would be exposed to if they stayed at home more o
Ostrovityanka [42]

Answer:

a) The study is an observational study

b) The proportion of children with significant social activity in children with acute lymphoblastic leukemia is approximately 0.802

The proportion of children with significant social activity in children without acute lymphoblastic leukemia is approximately 0.8565

c) The odds ratio is approximately 0.6780

d) The 95% CI is approximately 0.523 < OR < 0.833

e) i) Yes

ii) Children with more social activity have a higher occurrence of acute lymphoblastic leukemia

Step-by-step explanation:

a) An experimental study is a study in which the researcher adds inputs to the study and then monitors the outcomes

An observational study is one in which the researcher observes risk factors and does not intervene in the process

Therefore, the study is an observational study

b) The proportion of children with significant social activity in children with acute lymphoblastic leukemia is \hat p_1 = 1020/1272 = 85/106 = 0.8\overline {0188679245283} ≈ 0.802

The proportion of children with significant social activity in children without acute lymphoblastic leukemia is \hat p_2 = 5343/6238 ≈ 0.8565

c) We have the following two way table;

\begin{array}{ccc}Lymphoblastic \ Leukemia &With \ Social \ Activity & Without \ Social \ Activity\\With&1020 \ (a)&252 \ (b)\\Without&5343 \ (c)&895 \ (d) \end{array}

The \ odds \ ratio = \dfrac{1,020 \times 895}{5,343 \times 252} \approx 0.6780

The odds ratio ≈ 0.6780

d) The 95% confidence interval for the odds ratio is given as follows;

95 \% \ CI = OR \ \pm \ 1.96 \times \sqrt{\dfrac{1}{a} +\dfrac{1}{b}+\dfrac{1}{c}+\dfrac{1}{d}}

Where;

a = 1020, b = 252, c = 5343, d = 895

Therefore;

95 \% \ CI \approx  0.6780 \ \pm \ 1.96 \times \sqrt{\dfrac{1}{1,020} +\dfrac{1}{252}+\dfrac{1}{5,343}+\dfrac{1}{895}} \approx 0.678 \pm0.155

The 95% CI ≈ 0.523 < OR < 0.833

e) i) Given that the observed Odds Ratio is within the Confidence Interval, therefore, there is an indication that the amount of social activity is associated with acute lymphoblastic leukemia

ii) Based on the proportion of the study findings, children with more social activity have a higher occurrence of acute lymphoblastic leukemia

6 0
2 years ago
A student raises her grade average from a 75 to a 90. what was the percent of increase in the student's grade average? round you
Leona [35]
Here are some formulas...
percent increase = (new number - original number) / original number...* 100
percent decrease = (original number - new number) / original number...* 100
============
a student raises her grade from a 75 to a 90....since it is going from a smaller number to a larger number, u have an increase
percent increase = (90 - 75) / 70....* 100
                           =   15/70   * 100
                           = 0.2142 * 100
                           = 21.42 rounds to 21.4%  increase
-------------------------
36.50 on sale for 32.12...since it goes from a larger number to a smaller number, u have a decrease
percent decrease = (original number - new number) / original * 100
                             = (36.50 - 32.12) / 32.12...* 100
                             = 4.38 / 32.12...* 100
                             = 0.1363...* 100
                             = 13.63 rounds to 13.6% decrease
------------------------------
23.5 to 21.2......this is a decrease
percent decrease = (original number - new number) / original...* 100
                            = (23.5 - 21.2) / 23.5....* 100
                            = 2.3 / 23.5....* 100
                            = 0.0979 * 100
                            = 9.79 rounds to 9.8% decrease






3 0
3 years ago
Read 2 more answers
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