Answer:
666.888.000.333
Step-by-step explanation:
yeah I said what I said
bye
Determine whether the relation is a function. {(−3,−6),(−2,−4),(−1,−2),(0,0),(1,2),(2,4),(3,6)}
Semmy [17]
Answer:
Yes, this is a function
Step-by-step explanation:
This relation is function because 1 x value corresponds to 1 y value
Answer:
0.047619
P.S. do you need to round?
Answer:
See below
Step-by-step explanation:
1: (b+1)*(3b)*(b-5)
(3b^2+3b)(b-5)
3b^3-15b^2+3b^2-10b
3b^3-12b^2-10b
2: πr^ 2(h/3)
π(n-2)^2(12n/3)
π(n-2)(n-2)(12n/3)
π(n^2-2n-2n+4)(12n/3)
π(n^2-4n+4)(12n/3)
π(n^2-4n+4)(4n)
π(4n^3-16n^2+16n)
<em>(I'm not 100% sure with this one)</em>
3: (lwh)/3
((k-2)(2k+3)(3k))/3
((2k^2-4k+3k-6)(3k))/3
(6k^3-12k^2+9k^2-18k)/3
(6k^3-3k^2-18k)/3
2k^3-k^2-6k
