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3 years ago

2/7 divided by 6, fastest answer (and correct) gets brainest.

Mathematics

2 answers:

laiz [17]3 years ago

3 0

Answer:

0.047619

P.S. do you need to round?

morpeh [17]3 years ago

3 0

Answer:

$\frac{1}{21}$

Step-by-step explanation:

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Answers are A. 41 degrees B. 15 degrees C.90 degrees D. 83 degrees

SVETLANKA909090 [29]

Answer:

Step-by-step explanation:

Ok so what you are going to do is set up and equation where 6x-7=4x-23

you will get x= -8 now plug it in

5 0

3 years ago

Please help me solve this!!!!!!

BabaBlast [244]

Answer:

C. 9

Step-by-step explanation:

y = -4x^2 + 2kx

subtitute 3:

y = -4(9)^2 + 2k(9)

y = -4(81) + 18k

let y = 0

=> 0 = -324 + 18k

=> k = 324/18 = 9

this is my calculations hope it helps

4 0

2 years ago

Read 2 more answers

Find the GCF. 18c3 and 24c3

12345 [234]

Answer:

6c³

Step-by-step explanation:

18c³ = 2 × 3 × 3 × c × c × c

24c³ = 2 × 2 × 2 × 3 × c × c × c

Now we show the common factors in bold:

18c³ = 2 × 3 × 3 × c × c × c

24c³ = 2 × 2 × 2 × 3 × c × c × c

The common factor are:

2, 3, c, c, c

GCF = 2 × 3 × c × c × c = 6c³

6 0

3 years ago

What is the correct plural form of "una bebida popular"?

Olegator [25]

The answer is C!!!! hope this helps!

6 0

3 years ago

Read 2 more answers

Someone help me out please

uysha [10]

1 step (B): raise both sides of the equation to the power of 2.

$(\sqrt{x+3}-\sqrt{2x-1})^2=(-2)^2,\\ (x+3)-2\sqrt{x+3}\cdot \sqrt{2x-1}+(2x-1)=4,\\ 3x+2-2\sqrt{x+3}\cdot \sqrt{2x-1}=4$ .

2 step (A): simplify to obtain the final radical term on one side of the equation.

$-2\sqrt{x+3}\cdot \sqrt{2x-1}=4-3x-2,\\ -2\sqrt{x+3}\cdot \sqrt{2x-1}=2-3x,\\ 2\sqrt{x+3}\cdot \sqrt{2x-1}=3x-2$ .

3 step (F): raise both sides of the equation to the power of 2 again.

$(2\sqrt{x+3}\cdot \sqrt{2x-1})^2=(3x-2)^2,\\ 4(x+3)(2x-1)=(3x-2)^2$ .

4 step (E): simplify to get a quadratic equation.

$4(2x^2-x+6x-3)=(3x)^2-2\cdot 3x\cdot 2+2^2,\\ 8x^2+20x-12=9x^2-12x+4,\\ x^2-32x+16=0$ .

5 step (D): use the quadratic formula to find the values of x.

$D=(-32)^2-4\cdot 16=1024-64=960, \\ \sqrt{D} =8\sqrt{5} ,\\ x_{1,2}=\dfrac{32\pm 8\sqrt{5}}{2} =16\pm 4\sqrt{5}$ .

6 step (C): apply the zero product rule.

$x^2-32x+16=(x-16-4\sqrt{5}) (x-16+4\sqrt{5}) ,\\ (x-16-4\sqrt{5}) (x-16+4\sqrt{5}) =0,\\ x_1=16+4\sqrt{5} ,x_2=16-4\sqrt{5}$ .

Additional 7 step: check these solutions, substituting into the initial equation.

3 0

3 years ago