If scores on an exam follow an approximately normal distribution with a mean of 76.4 and a standard deviation of 6.1 points, then the minimum score you would need to be in the top 2% is equal to 88.929.
A problem of this type in mathematics can be characterized as a normal distribution problem. We can use the z-score to solve it by using the formula;
Z = x - μ / σ
In this formula the standard score is represented by Z, the observed value is represented by x, the mean is represented by μ, and the standard deviation is represented by σ.
The p-value can be used to determine the z-score with the help of a standard table.
As we have to find the minimum score to be in the top 2%, p-value = 0.02
The z-score that is found to correspond with this p-value of 0.02 in the standard table is 2.054
Therefore,
2.054 = x - 76.4 ÷ 6.1
2.054 × 6.1 = x - 76.4
12.529 = x - 76.4
12.529 + 76.4 = x
x = 88.929
Hence 88.929 is calculated to be the lowest score required to be in the top 2%.
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X= 19/12 which is 1.58 in decimal form
Answer:
When we have a discount of X% of the original price, the new price is calculated as:
New price = (original price) - (original price)*(X%/100%)
In our case, let's define:
P = original price of the fishing pole
f = price of the fishing pole after the discount
X% = 20%
Then the equation for the price of the fishing pole is:
f = P - P*(20%/100%) = P - P*0.2 = P*(1 - 0.2) = P*0.8
f = 0.8*P
This means that the price after the discount is 0.8 times the original price.
Answer: 56
Step-by-step explanation:
The way to answer this question is to first make 52% into a decimal:
52% = 0.52
so now we will simply multiply:
84
x.52
once you have multiplied these numbers it comes out to be 43.68.
So your answer is 43.68.
Hope this answer helps! feel free to ask any additional questions :)
