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2 years ago

5

Ava plays on the softball team at her school. The team won 8 of its first 12 games. At that rate, how many games will Ava's team

win if it plays 60 games in all?

1 answer:

GaryK [48]2 years ago

3 0

Answer:

She wins 40 games

Step-by-step explanation:

I'm not the best at explaining but 5x12=60 so then we multiply 8 by 5 aswell and bam we have 40.

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irina1246 [14]

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3 years ago

Please help i dont get this at all

Tom [10]

Answer:

$\frac{20y^{2} a^{2} }{41bx^{3} }$

Step-by-step explanation:

1) Flip the second fraction and change the operation to multiplication:

$\frac{5x^{2}y^{3} }{2a^{5}b^{4} } * \frac{8a^{7}b^{3} }{41x^{5}y }$

2) Cross cancel factors:

$\frac{5y^{2} }{2b } * \frac{8a^{2} }{41x^{3} }$

3) Multiply:

$\frac{40y^{2} a^{2} }{82bx^{3} }$

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3 years ago

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forsale [732]

Answer:

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Step-by-step explanation:

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3 years ago

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Dont do QA <br> plzzzzzzzzzzzzzzzzzzzzzzzz

N76 [4]

Answer:

$(a) x^2-2x=x \times (x+2) \\\\(b) 6x^2+12x=2\times 3 \times x \times ( x + 2) \\\\(c) 3x^3 - 9x=3\times x \times (x^2 -3) \\\\(d) 4x^2 +28 x^3 = 2 \times 2 \times x \times x \times ( 1+ 7x)$

Step-by-step explanation:

To factorize, at first, do factorize all the terms then take the common terms out.

(a) $x^2-2x$

This can be written as

$x^2-2x= x\times x + 2 \times x$

Now, taking x commom from both the terms.

$x^2-2x=x \times (x+2)$

(b) $6x^2+12x$

$=2\times 3 \times x\times x + 2\times 2 \times 3 \times x$

Now, taking $2\times 3\times x$ common from both the terms, we have

$6x^2+12x=2\times 3 \times x \times ( x + 2)$

This is the required factorization.

(c) $3x^3 - 9x \\\\$

$= 3 \times x \times x \times - 9\times x \\\\ 3x^3 - 9x=3\times x \times (x^2 -3)$

This is the required factorization.

(d) $4x^2 +28 x^3$

$= 2 \times 2 \times x \times x + 2 \times 2 \times 7 \times x \times x \times x \\\\4x^2 +28 x^3 = 2 \times 2 \times x \times x \times ( 1+ 7x)$

This is the required factorization.

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3 years ago