Given the table below which shows the result of a survey that asked 2,881 people whether they are involved in any type of charity work.
![\begin{tabular} {|c|c|c|c|c|c|} &Frequently&Occassionally&Not at all&Total\\[1ex] Male&227&454&798&1,479\\ Female &205&450&747&1,402\\ Total&432&904&1,545&2,881 \end{tabular}](https://tex.z-dn.net/?f=%5Cbegin%7Btabular%7D%0A%7B%7Cc%7Cc%7Cc%7Cc%7Cc%7Cc%7C%7D%0A%20%26Frequently%26Occassionally%26Not%20at%20all%26Total%5C%5C%5B1ex%5D%0AMale%26227%26454%26798%261%2C479%5C%5C%0AFemale%20%26205%26450%26747%261%2C402%5C%5C%0ATotal%26432%26904%261%2C545%262%2C881%0A%5Cend%7Btabular%7D)
Part A:
If a person is chosen at random, the probability that the person is frequently or occassinally involved in charity work is given by

Part B:
If a person is chosen at random, the probability that the person is female or not involved in charity work at all is given by

Part C:
If a person is chosen at random, the probability that the person is male or frequently involved in charity work is given by

Part D:
If a person is chosen at random, the probability that the person is female or not frequently involved in charity work is given by

Part E:
The events "being female" and "being frequently involved in charity work" are not mutually exclusive because being a female does not prevent a person from being frequently involved in charity work.
Indeed from the table, there are 205 females who are frequently involved in charity work.
Therefore, the answer to the question is "No, because 205 females are frequently involved charity work".
Only letter a has an answer. Pls. see attachment.<em>
</em>
The probability that one cubic meter of discharge contains at least 8 organisms is 0.7798
Answer:
adult tickets = 17, children tickets = 9
Step-by-step explanation:
Let x be the number of children and y the number of adults
Then given that 26 tickets are sold, we can write
x + y = 26 → (1)
Given that ticket cost was $194 we can write
5.5x + 8.5y = 194 → (2)
Rearrange (1) expressing y in terms of x by subtracting x from both sides
y = 26 - x → (3)
Substitute y = 26 - x into (2)
5.5x + 8.5(26 - x) = 194 ← distribute and simplify left side
5.5x + 221 - 8.5x = 194
- 3x + 221 = 194 ( subtract 221 from both sides )
- 3x = - 27 ( divide both sides by - 3 )
x = 9
Substitute x = 9 into (3) for corresponding value of y
y = 26 - 9 = 17
Hence number of adult tickets sold = 17
number of children tickets sold = 9
Amount saved:50I60I70l80l AND ON......
......weeks......:0..I1...l2..l3..l ..........AND ON
amount saved =x
weeks=y
after every y+10=x