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Oksi-84 [34.3K]
3 years ago
6

The low temperature for 5 days was -5, -7, -2, 2, -3 degrees. What was the average low temperature for those days?

Mathematics
1 answer:
Greeley [361]3 years ago
5 0

The average would be -3. You add all the low temps up and get -15 then you divide it by the amount which was 5 temps... And get -3.

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I need help please hurry.
Anarel [89]

Answer:the answer is the first

Step-by-step explanation:

Because the expression can be written as -10r2/2r2+4+5r/2r2+4+3/2r2+4

8 0
3 years ago
X, Y, and Z are collinear and Y is between X and Z. If XY = 3x – 1, YZ = 5, and XZ = 5x – 8,
salantis [7]

Answer:

6

Step-by-step explanation:

XY = 3x – 1, YZ = 5, and XZ = 5x – 8,

We know that XY + YZ = XZ, so

3x - 1 + 5 = 5x - 8

3x + 4 = 5x - 8

3x + 12 = 5x

12 = 2x

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4 0
3 years ago
Which ratio is porportional to 18/21? A.2/3 B. 30/35 C. 36/48 D.1/3
defon
You can solve this problem by applying the proccedure below:
 
 You have:
 
 a) 18/21=2/3
 18x3/21x2
 36≠42 (2/3 is not proportinal to 18/21).
 
 b)18/21=30/35
 18x35/21x30
 630=630  (30/35 is proportional to 18/21)
 
 c)18/21=36/48
 18x48/21x36
 864≠756  (36/48<span> is</span><span> not proportinal to 18/21)
</span> 
 d)18/21=1/3
 18x3/21x1
 54≠21  (<span> 1/3 is</span><span> not proportinal to 18/21)
</span> 
 Therefore, you can conclude that the correct option is: B.30/35
8 0
3 years ago
1. Solve the equation. 2. Check your solution. k÷3=21
Sedaia [141]

Answer:

k = 63

Step-by-step explanation:

3 x 21 = 63

8 0
3 years ago
A group of high school athletes has an average GPA of 2.7 with a standard deviation of 0.9. a)Find the percentage of athletes wh
mart [117]

Answer:

a) The percentage of athletes whose GPA more than 1.665 is 87.49%.

b) John's GPA is 3.645.

Step-by-step explanation:

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 2.7, \sigma = 0.9

a)Find the percentage of athletes whose GPA more than 1.665.

This is 1 subtracted by the pvalue of Z when X = 1.665. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{1.665 - 2.7}{0.9}

Z = -1.15

Z = -1.15 has a pvalue of 0.1251

1 - 0.1251 = 0.8749

The percentage of athletes whose GPA more than 1.665 is 87.49%.

b) John's GPA is more than 85.31 percent of the athletes in the study. Compute his GPA.

His GPA is X when Z has a pvalue of 0.8531. So it is X when Z = 1.05.

Z = \frac{X - \mu}{\sigma}

1.05 = \frac{X - 2.7}{0.9}

X - 2.7 = 1.05*0.9

X = 3.645

John's GPA is 3.645.

8 0
3 years ago
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