Not necessarily.
and
may be linearly dependent, so that their span forms a subspace of
that does not contain every vector in
.
For example, we could have
and
. Any vector
of the form
, where
, is impossible to obtain as a linear combination of these
and
, since
unless
and
.
Answer:
no solution
Step-by-step explanation:
2x + 4y = 6......reduces to x + 2y = 3
3x = 12 - 6y....reduces to x = 4 - 2y...rearranged is x + 2y = 4
so now we have :
x + 2y = 3
x + 2y = 4
ok....I dont have to go any farther to know that this has no solution because ur equations have the same slope and different y int, this means ur lines are parallel and have no solution because they never cross each others path.
6 √5
7 π
Both continue on forever and will never have an exact answer - therefore, they're irrational.
5 · 5 - 4 · 4 = 9 sorry if I'm wrong
the dots mean to multiply
Two triangles are similar if and only if all corresponding angles are equal (congruence), even if the corresponding sides are equal or not, therefore the answer is true because ΔJKL and ΔRST are similar and the statement above demands that "it must be", namely, this is a sufficient condition.
