Can someone help me find the volume of this shape then round to the nearest 10th?

Mathematics

1 answer:

Gwar [14]4 years ago

8 0

The volume of a cylinder is pi*r^2*h

We have a radius of 7/2=3.5 cm, and a height of 11.5 cm

So we plug in: pi*3.5^2*11.5=442.5718651

Rounded to the nearest tenth is 442.6 cm^3

Hope this helped!

You might be interested in

Does 5mm, 1mm, 10mm make a triangle

pogonyaev

Answer:

Step-by-step explanation:

No. Each side must be less than the sum of the remaining two sides.

10 ≮ 5+1

6 0

2 years ago

a parking garage has 6 levels. Each level has 15 row. Each row has the same number of parking spaces. there are 2,250 parking sp

Mandarinka [93]

To start with, we know there’s a definite amount of parking spaces in all(2,250) and we also know each level(6 in all) had 15 rows of parking spaces.

Equation

A = Parking spots per row

A = 2,250 Divided by(6 levels times 15 rows)

A= 2,250 Divided by 90

A = 25

The correct answer is 25 parking spots per row

To check this answer we can do

25 spots per row, Times 15 rows per level, Times the total amount of levels (6)

= the total amount of parking spots

25*15*6= 2,250

True

This confirms this answer as correct. Hope this helps.

6 0

2 years ago

Kiesha and her classmates wrote proportions for the reduction of a triangle. A larger and smaller triangle have corresponding he

MrMuchimi

Answer:

the 2nd one

Step-by-step explanation:

mecause its new=original

6 0

3 years ago

Read 2 more answers

1. Multiply using distributive property.

RoseWind [281]

Answer:

The distributive property tells us how to solve expressions in the form of a(b + c). The distributive property is sometimes called the distributive law of multiplication and division.

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Suppose there is a pile of quarters dimes and pennies with a total value of $1.07 how much of each coin can be present without b

Korolek [52]

Hello,

Very nice as problem.

2 solutions:
1 quater,8 dimes, 2 pennies
and
3 quaters,3 dimes, 2 pennies

since
107=( 0, 0, 107) but : 100= 0*25+ 0*10+ 100
107=( 0, 1, 97) but : 100= 0*25+ 1*10+ 90
107=( 0, 2, 87) but : 100= 0*25+ 2*10+ 80
107=( 0, 3, 77) but : 100= 0*25+ 3*10+ 70
107=( 0, 4, 67) but : 100= 0*25+ 4*10+ 60
107=( 0, 5, 57) but : 100= 0*25+ 5*10+ 50
107=( 0, 6, 47) but : 100= 0*25+ 6*10+ 40
107=( 0, 7, 37) but : 100= 0*25+ 7*10+ 30
107=( 0, 8, 27) but : 100= 0*25+ 8*10+ 20
107=( 0, 9, 17) but : 100= 0*25+ 9*10+ 10
107=( 0, 10, 7) but : 100= 0*25+ 10*10+ 0
107=( 1, 0, 82) but : 100= 1*25+ 0*10+ 75
107=( 1, 1, 72) but : 100= 1*25+ 1*10+ 65
107=( 1, 2, 62) but : 100= 1*25+ 2*10+ 55
107=( 1, 3, 52) but : 100= 1*25+ 3*10+ 45
107=( 1, 4, 42) but : 100= 1*25+ 4*10+ 35
107=( 1, 5, 32) but : 100= 1*25+ 5*10+ 25
107=( 1, 6, 22) but : 100= 1*25+ 6*10+ 15
107=( 1, 7, 12) but : 100= 1*25+ 7*10+ 5
107=( 1, 8, 2) is good
107=( 2, 0, 57) but : 100= 2*25+ 0*10+ 50
107=( 2, 1, 47) but : 100= 2*25+ 1*10+ 40
107=( 2, 2, 37) but : 100= 2*25+ 2*10+ 30
107=( 2, 3, 27) but : 100= 2*25+ 3*10+ 20
107=( 2, 4, 17) but : 100= 2*25+ 4*10+ 10
107=( 2, 5, 7) but : 100= 2*25+ 5*10+ 0
107=( 3, 0, 32) but : 100= 3*25+ 0*10+ 25
107=( 3, 1, 22) but : 100= 3*25+ 1*10+ 15
107=( 3, 2, 12) but : 100= 3*25+ 2*10+ 5
107=( 3, 3, 2) is good
107=( 4, 0, 7) but : 100= 4*25+ 0*10+ 0

4 0

3 years ago