Answer:
40 square units
Step-by-step explanation:
First of all, lets say that square has side
, so, the area unit is ![l^2](https://tex.z-dn.net/?f=l%5E2)
the diagonal's square is ![l\sqrt{2}](https://tex.z-dn.net/?f=l%5Csqrt%7B2%7D)
CALCULATION OF TRIANGLES'S AREA (there are 4 triangles)
![A_{triangles}=4*base*heigh*0.5=2*(l\sqrt{2} )(2l\sqrt{2} )=8l^2](https://tex.z-dn.net/?f=A_%7Btriangles%7D%3D4%2Abase%2Aheigh%2A0.5%3D2%2A%28l%5Csqrt%7B2%7D%20%29%282l%5Csqrt%7B2%7D%20%29%3D8l%5E2)
CALCULATION OF MAIN SQUARE AREA
![A_{square}=side*side=(4\sqrt{2} l)(4\sqrt{2} l)=32l^2](https://tex.z-dn.net/?f=A_%7Bsquare%7D%3Dside%2Aside%3D%284%5Csqrt%7B2%7D%20l%29%284%5Csqrt%7B2%7D%20l%29%3D32l%5E2)
TOTAL AREA
![A_{total}=A_{triangles}+A_{square}=8l^2+32l^2=40l^2](https://tex.z-dn.net/?f=A_%7Btotal%7D%3DA_%7Btriangles%7D%2BA_%7Bsquare%7D%3D8l%5E2%2B32l%5E2%3D40l%5E2)
Answer:
41x² - 27x + 27
Step-by-step explanation:
Perimeter of Rectangle:
= 2(20x²-12x+4) + 2(5x²-5x+15)
= 40x²-24x+8 + 10x²-10x+30
= 50x²-34x+38
Perimeter of Triangle:
= 6x²+6x+3x+3+3x²-2x+8
= 9x²+7x+11
Difference:
(50x²-9x²)+(-34x+7x)+(38-11)
= 41x² - 27x + 27
The answer is you add 0.05 every time
Answer:
Her eye discourses; I will answer it.
I am too bold; ’tis not to me she speaks:
Two of the fairest stars in all the heaven,
Having some business, do entreat her eyes
To twinkle in their spheres till they return.
Step-by-step explanation: