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Pani-rosa [81]
3 years ago
12

2. The distance between Belmont and

Mathematics
1 answer:
Delvig [45]3 years ago
7 0
Divide 18 by 2 you get 9
then 1cm= 9miles
so 3cm= 27miles
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there are 28 students in a classroom. the ratio girls to boys 4 to 3. write and solve a proportion to find how many boys are the
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Total = 28

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4. 3

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3 0
3 years ago
The combined area of a square and a rectangle is 225 square yards. the length of the rectangle is 8 times the width of the recta
snow_lady [41]

Answer:

The rectangle:  <u>L = 40 yards.   W = 5 yards</u>

The square: The length and width are both <u>5 yards</u>.

Step-by-step explanation:

<u>Let L and W be the length and width of the rectangle. </u>

<u>Let l and w be the length and width of the square.</u>

Area for each is:

Rectangle:  L*W

Square:       l*w

We are told that <u>L*W + l*w = 225 yards^2</u>

We are also told that

<u>L = 8W </u>

and that

<u>l = W</u>

Since the sides of a square are all equal, w is also W:  <u>w=W</u>

Summarizing and substituting:

L*W + l*w = 225 yards^2

(8W)*W + W*W = 225 yards^2

8W^2 + W^2 = 225 yards^2

9W^2  = 225 yards^2

W^2 = 25

W = 5 feet

---------------------

Therefore, since L = 8W <u>,</u> <u>L = 40 yards.   W = 5 yards</u> for the rectangle.

The square:  l=W, so <u>l = 5 yards, and thus w=5 yards</u>

--------------------------

Check:

Do a rectangle of 40' x 5' plus a square of 5' x 5' have a total combined area of 225 yards^2?

40yd x 5yd + 5yd x 5yd = 225 yards^2?

200 yd^2 + 25 yd^2 = 225 yards^2?

YES

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V = πr²l
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<span>V = 226.19 in³ water needed</span>
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Name at least one advantage of credit cards.
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You are able to pay expensive dues forward, such as houses, cars, and other payments that you wouldn't be able to pay in full on the spot.
3 0
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