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Mariana [72]
3 years ago
9

What is the volume in cubic inches of the cylinder, rounded to the nearest cubic inch?

Mathematics
1 answer:
son4ous [18]3 years ago
7 0

\bf \textit{volume of a cylinder}\\\\ V=\pi r^2 h~~ \begin{cases} r=radius\\ h=height\\ \cline{1-1} r=9\\ h=7 \end{cases}\implies V=\pi (9)^2(7) \\\\\\ V=\pi (81)(7)\implies V=567\pi \implies V\approx 1781.28\implies \stackrel{\textit{rounded up}}{V=1781}

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MrRissso [65]

we have

y=7x^{2}-10

To find the inverse

Step 1

Exchanges the variables, x for y and y for x

x=7y^{2}-10

Step 2

Isolate the variable y

x=7y^{2}-10

7y^{2}=x+10

y^{2}= \frac{x+10}{7}

Square Root both sides

y=(+/-)\sqrt{\frac{x+10}{7}}

Step 3

Let

f(x)^{-1}=y

so

f(x)^{-1}=(+/-)\sqrt{\frac{x+10}{7}}

therefore

<u>the answer is</u>

The inverse is  

f(x)^{-1}=(+/-)\sqrt{\frac{x+10}{7}}

8 0
3 years ago
Read 2 more answers
You are in the electronics store purchasing a video game that retails for 45$ the sales tax charged on the game is 2.70 what is
Katyanochek1 [597]

Answer:

6%

Step-by-step explanation:

let 't' = tax rate

45t = 2.7

t = 2.7/45

t = .06

8 0
3 years ago
Y varies directly as xy equals 5 when X is 8 how do you find y when X is 9
FrozenT [24]

Given, y varies directly as x

So,

y=c\cdot x

Where c is a constant

When y equals 5 when x is 8

So,

\begin{gathered} 5=c\cdot8 \\ c=\frac{5}{8} \\  \end{gathered}

So, the relation between y and x

y=\frac{5}{8}x

now , when x = 9

Substitute with x to find y

y=\frac{5}{8}\cdot9=\frac{45}{8}

So, the answer is option 2. y = 45/8

5 0
1 year ago
The half-life of a radioactive isotope is the time it takes for a quantity of the isotope to be reduced to half its initial mass
krok68 [10]
So, 0.5^5 is 0.03125
multiply that by 125 and get your answer.
*3.90625* (4)
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If it were to gain, you would put 1.5

7 0
3 years ago
True or false: in order to fill the following box, you would need to fill in 2 unit cubes in length, 2 unit cubes in width, and
tensa zangetsu [6.8K]

Answer:

Step-by-step explanation:

True

7 0
3 years ago
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