Answer:
a1 = 39, a2 = 41, a3 = 43
The pair with the greatest sum is a2 + a3 = 41 + 43 = 84
Step-by-step explanation:
Let the first integer be a1 = a.
Let the second odd integer be a2 = a + 2
Let the third odd integer be a3 = (a + 2) + 2 = a + 4
The sum of three consecutive odd integers is 123.
123 = a1 + a2 + a3
123 = a + (a + 2) + (a + 4)
123 = 3a + 6
117 = 3a
a = 39
a1 = a = 39
a2 = a + 2 = 39 + 2 = 41
a3 = a + 4 = 39 + 4 = 43
The pair with the greatest sum is a2 + a3 = 41 + 43 = 84
Hey there! :)
PARENTHESES
EXPONENTS
MULTIPLICATION
DIVISION
ADDITION
SUBTRACTION
First is multiplying
54 × 56 = 3,024
Now, add 9
3,024 + 9 = 3,033
At last, add y
3,033 + y = 3,033 + y
Your answer is: 3,033 + y
Hope this helps :)
Answer:
X=-1
Step-by-step explanation:
It’ll probably look like this if so..
-8/10,-12/15,-16/20,-20/25,-24/30,etc.
Answer:
function
Step-by-step explanation:
hoped this helped;)
