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3 years ago

In a relation, the input is the number of people and the output is the number of watches

Mathematics

2 answers:

irinina [24]3 years ago

6 0

Answer:

Step-by-step explanation:

Not a function. The number of people has little direct connection with the total number of watches owned.

olga55 [171]3 years ago

4 0

Answer:

function

Step-by-step explanation:

hoped this helped;)

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Wanda started walking along a path 27 seconds before Dave. Wanda walked at a constant rate of 3 feet per second. Dave walked alo

Advocard [28]

Answer:

Wanda and Dave will catch each other in 54 seconds after Dave starts walking.

Step-by-step explanation:

Let Wanda and Dave catch each other when x be the time after Dave starts walking and y be the distance covered by them

It is given that Wanda started walking along a path 27 seconds before Dave and the constant speed of Wanda is 3 feet per second.

$speed=\frac{distance}{time}$

$3=\frac{y}{x+27}$

$y=3(x+27)$

$y=3x+81$ .... (1)

The constant speed of Dave is 4.5 feet per second.

$4.5=\frac{y}{x}$

$y=4.5x$ .... (2)

Equate equation (1) and (2).

$3x+81=4.5x$

$81=1.5x$

Divide both sides by 1.5.

$\frac{81}{1.5}=x$

$54=x$

Therefore, Wanda and Dave will catch each other in 54 seconds after Dave starts walking.

6 0

4 years ago

PLEASE HURRY IM ALREADY HAVING AN AWFUL DAY :) WILL. GIVE BRAINLIEST

Art [367]

Answer:

well its D

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Use the Distance Formula and the Pythagorean Theorem to find the distance between each pair of points. M (10, −4) and N (2, −7)

xenn [34]

Answer:

$d=\sqrt{73}\approx8.54$

Step-by-step explanation:

So we have the two points (10,-4) and (2,-7).

And we want to find the distance between them using the Distance Formula and the Pythagorean Theorem. Let's do each one individually.

1) Distance Formula.

The distance formula is:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2$

Let's let (10,-4) be (x₁, y₁) and let's let (2,-7) be (x₂, y₂). So:

$d=\sqrt{((2)-(10))+((-7)-(-4))^2$

Simplify:

$d=\sqrt{(2-10)^2+(-7+4)^2$

Subtract:

$d=\sqrt{(-8)^2+(-3)^2$

Square:

$d=\sqrt{64+9}$

Add:

$d=\sqrt{73}$

Approximate:

$d\approx8.54$

So, the distance between (10,-4) and (2,-7) is approximately 8.54 units.

2) Pythagorean Theorem

Please refer to the graph.

So, we want to find the distance. This will be the length of the red line, or the hypotenuse.

First, let's find the length of the two legs.

The longer leg will be the difference between the two x-coordinates. So, the length of the longer leg is:

$(10-2)=8$

Note: It doesn't matter if we do 2-10, which gives -8, since we are going to square anyways. Also, distance is always positive, so 8 would be our answer.

And the shorter leg is the difference between the two y-coordinates. Namely:

$(-7-(-4))=-3=3$

So, the shorter leg is 3 units.

So now, we can use the Pythagorean Theorem, which is:

$a^2+b^2=c^2$

Substitute 8 for a and 3 for b. So:

$(8)^2+(3)^2=c^2$

Square:

$64+9=c^2$

Add:

$c^2=73$

Take the square root:

$c=\sqrt{73}\approx8.54$

This is the same as our previous answer, so we can confirm that it's correct.

So, using both the distance formula and the Pythagorean Theorem, the distance between the two points is approximately 8.54.

And we're done!

5 0

3 years ago

Read 2 more answers

Choose the equation that represents the line that passes through the point (6,-3,) and has a slope of 1/2

dezoksy [38]

Answer:

$y=\frac{1}{2}x-6$

Step-by-step explanation:

The general equation of a line: $y = ax+b$

In our case a is given

$a=\frac{1}{2}$

Now we plug in for a and we get:

$y=\frac{1}{2}*x+b$

Now we plug in our coordinates into this equation and we solve for b

$-3=\frac{1}{2}*6+b\\b = -6$

So the equation of the line is $y=\frac{1}{2}x-6$

6 0

4 years ago

Read 2 more answers

Consider the function g(x) below. What are the values of the function when x=0 and x=6.

Sliva [168]

Answer:

Consider the function below. g(x) = 250 + 8x^3 + x^4 (a) Find the interval of increase. (Enter your answer in interval notation.) Find the interval of decrease. (Enter your answer in interval notation.) (b) Find the local minimum value(s). (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE.) Find the local maximum value…

Step-by-step explanation:

You have to study

3 0

3 years ago