Question

What is the distance rounded to the nearest tenth, between the points (0, 5) and (8, 0)?

Answer 1

Answer:

$\huge\boxed{\sf 9.4 \ units}$

Step-by-step explanation:

Coordinates are (0,5) and (8,0)

$\sf Distance\ Formula = \sqrt{(x2-x1)^2 + (y2-y1)^2} \\\\D = \sqrt{(8-0)^2 + (0-5)^2} \\\\D = \sqrt{8^2 + (-5)^2} \\\\D = \sqrt{64+25} \\\\D = \sqrt{89} \\\\D = 9.4\ units$

Answer 2

Answer:

Vvvgfffff

Step-by-step explanation: