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3 years ago

Romb ma obwód równy 32 cm. Jakie jest pole tego rombu, jeżeli jego wysokość ma 3 cm?

Mathematics

1 answer:

Goshia [24]3 years ago

8 0

Answer:

24 cm²

Step-by-step explanation:

Z zadanego powyżej pytania uzyskano następujące dane:

Obwód (obwód) = 32 cm

Wysokość (h) = 3 cm

Obszar rombu (A) =?

Następnie określimy długość boku rombu. Można to uzyskać w następujący sposób:

Obwód, czyli obwód (P) = 32 cm

Strona (y) =?

P = 4 s

32 = 4 s

Podziel obie strony przez 4

s = 32/4

s = 8 cm

Stąd długość boku rombu wynosi 8 cm

Na koniec określimy obszar rombu w następujący sposób:

Długość boków = 8 cm

Wysokość (h) = 3 cm

Obszar rombu (A) =?

A = sh

A = 8 × 3

A = 24 cm²

Dlatego obszar rombu jest

24 cm².

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I really need help!!!

Zigmanuir [339]

Answer:

$Pr = 6.67\%$

Step-by-step explanation:

Given

$n = 10$ i.e. 10 people

Required

Probability of being next to each other

First, we calculate the total possible arrangements (without any restriction)

$Total = n!$

$Total = 10!$

If the three are to be next to each other,

First, we arrange the three

$r_1 = 3!$

Now, the 3 will be seen as 1; so, we have a total of 8 people i.e. (1 + 7 others)

The arrangement is:

$r_2 =8!$

So, the total arrangement, when they have to be next to one another is:

$r = r_1 * r_2$

$r = 3! * 8!$

The probability is:

$Pr = \frac{r}{n}$

$Pr = \frac{3! * 8!}{10!}$

Expand

$Pr = \frac{3*2*1 * 8!}{10*9*8!}$

$Pr = \frac{3*2*1}{10*9}$

$Pr = \frac{6}{90}$

$Pr = 0.0667$

Express as percentage

$Pr = 0.0667 * 100\%$

$Pr = 6.67\%$

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