coordinate of B= (2+3,0) = (5,0)
by pythagoras' theorem,
height of triangle^2 + half length of AB^2 = AC^2
height of triangle^2 = 3^2-1.5^2
height of triangle ^2= 6.75
height of triangle= √6.75
coordinates of C= (1.5,√6.75)
Where are the measurements?
Answer:
Square each side
Subtract 1 from each side
Divide by 3
Step-by-step explanation:
sqrt(3x+1) = 4
Square each side
(sqrt(3x+1))^2 = 4^2
3x+1 = 16
Subtract 1 from each side
3x+1-1 = 16-1
3x= 15
Divide by 3
3x/3 = 15/3
x = 5
Do Area = (base 1 + base2) × H
Answer:
Wait does it mean the actual real life distance or the distance on paper?
Step-by-step explanation:
If its real like just google it lol.
