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3 years ago

Please find the areas of the four rectangles and ADD them together. Fill in the spaces below.

Mathematics

1 answer:

Andrei [34K]3 years ago

4 0

Total area = 9 x5 =45
Total area = (6+3)(4+1)=24+6+12+3=45

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Ali has q quarters. Tom has four more quarters than Ali.

Anna35 [415]

Answer: x(.25)+(4+x(.25))=y

Step-by-step explanation:

1. set up the equation-

Ali has an unknown amount of quarters so make that x.

We know quarters are 25 cents so .25 if he has one quarter you put that one quarter into x, 2 into x and so on

Tom has 4 more, since he has 4 more it is 4+x and one again times .25

2. that is it

7 0

2 years ago

Use the discriminant to find the number and type of solution for x^2+6x=-9

likoan [24]

Answer:

D = 0; one real root

Step-by-step explanation:

Discriminant Formula:

$\displaystyle \large{D = {b}^{2} - 4ac}$

First, arrange the expression or equation in ax^2+bx+c = 0.

$\displaystyle \large{ {x}^{2} + 6x = - 9}$

Add both sides by 9.

$\displaystyle \large{ {x}^{2} + 6x + 9 = - 9 + 9} \\ \displaystyle \large{ {x}^{2} + 6x + 9 = 0}$

Compare the coefficients so we can substitute in the formula.

$\displaystyle \large{a {x}^{2} + bx + c = {x}^{2} + 6x + 9 }$

a = 1
b = 6
c = 9

Substitute a = 1, b = 6 and c = 9 in the formula.

$\displaystyle \large{D = {6}^{2} - 4(1)(9)} \\ \displaystyle \large{D = 36 - 36} \\ \displaystyle \large{D = 0}$

Since D = 0, the type of solution is one real root.

6 0

2 years ago

the measurements of a photo and it's frame are shown in the diagram. Write a polynomial that represents the width of the photo.

suter [353]

Answer:

The width of the photo is $4w^2+6w+4$ .

Step-by-step explanation:

From the given figure it is notices that the total width of the frame is

$6w^2+8$

The photo is covered by a frame border and the width of the border is

$w^2-3w+2$

To find the width of the photo we have to subtract the width of upper frame border and lower frame border from the total width of frame.

Width of the photo is

$\text{Width of the photo}=\text{Width of the frame}-2(\text{Width of the frame border})$

$\text{Width of the photo}=6w^2+8-2(w^2-3w+2)$

$\text{Width of the photo}=6w^2+8-2w^2+6w-4$

$\text{Width of the photo}=4w^2+6w+4$

Therefore the width of the photo is $4w^2+6w+4$ .

4 0

3 years ago

Write a fact with the same sum as 7+5

kaheart [24]

7+5=12 so it can be one of these 8+4=12, 9+3=12, 10+2=12, and 11+1=12.

5 0

2 years ago

What is 10 times 2.50?

dolphi86 [110]

Twenty five dollars answeris

4 0

3 years ago

Read 2 more answers