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gayaneshka [121]
3 years ago
15

Your Aunt Karen is shopping for flower pots at the local garden store. She has selected the type of pots shown below.

Mathematics
1 answer:
nevsk [136]3 years ago
8 0

Answer:stffu n!ger follow me on ig bennyamour

Step-by-step explanat

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Solve the following system x=3 y=3x-1
astraxan [27]

Answer:

x = 3

y = 8

Step-by-step explanation:

Since it gives you x, you need to plug in the number given for it into the equation:

y = 3x - 1

y = 3(3) - 1

y = 9 - 1

y = 8

So now you have, x = 3 and y = 8

5 0
3 years ago
Each year on the same day, Susan deposits $175 into a saving account that earns simple interest at a rate of 3.5%. She makes no
igomit [66]
The amount after time t will be given by simple interest formula given by:
A=prt/100
where:
principle,p=$175
rate, r=3.5%
time, t=5 years
thus the rate earned after 5 years will be:
A=(175*3.5/100*5)
A=$30.625
Answer: B] 30.65

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3 years ago
Simplify this equation, 12x+7x+8y+12^2+y+12=
soldi70 [24.7K]
12x+7x+8y+12^2+y+12=19x+9y+24^2
5 0
3 years ago
Read 2 more answers
The diameter of a circle is 9 m. Find the circumference to the nearest tenth.​
DerKrebs [107]

Answer:

Circumference = diameter × π

Take π =3. 14

  • 9×3. 14 = 28. 26 ~ 28. 3
5 0
3 years ago
Best known for its testing program, ACT, Inc., also compiles data on a variety of issues in education. In 2004 the company repor
GarryVolchara [31]

Answer:

\mu_p -\sigma_p = 0.74-0.0219=0.718

\mu_p +\sigma_p = 0.74+0.0219=0.762

68% of the rates are expected to be betwen 0.718 and 0.762

\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696

\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784

95% of the rates are expected to be betwen 0.696 and 0.784

\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674

\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806

99.7% of the rates are expected to be betwen 0.674 and 0.806

Step-by-step explanation:

Check for conditions

For this case in order to use the normal distribution for this case or the 68-95-99.7% rule we need to satisfy 3 conditions:

a) Independence : we assume that the random sample of 400 students each student is independent from the other.

b) 10% condition: We assume that the sample size on this case 400 is less than 10% of the real population size.

c) np= 400*0.74= 296>10

n(1-p) = 400*(1-0.74)=104>10

So then we have all the conditions satisfied.

Solution to the problem

For this case we know that the distribution for the population proportion is given by:

p \sim N(p, \sqrt{\frac{p(1-p)}{n}})

So then:

\mu_p = 0.74

\sigma_p =\sqrt{\frac{0.74(1-0.74)}{400}}=0.0219

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ).

\mu_p -\sigma_p = 0.74-0.0219=0.718

\mu_p +\sigma_p = 0.74+0.0219=0.762

68% of the rates are expected to be betwen 0.718 and 0.762

\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696

\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784

95% of the rates are expected to be betwen 0.696 and 0.784

\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674

\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806

99.7% of the rates are expected to be betwen 0.674 and 0.806

5 0
3 years ago
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