What is the range of this graph?
2 answers:
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Answer:
a) x=(t^2)/2+cos(t), b) x=2+3e^(-2t), c) x=(1/2)sin(2t)
Step-by-step explanation:
Let's solve by separating variables:
a) x’=t–sin(t), x(0)=1
Apply integral both sides:
where k is a constant due to integration. With x(0)=1, substitute:
Finally:
b) x’+2x=4; x(0)=5
Completing the integral:
Solving the operator:
Using algebra, it becomes explicit:
With x(0)=5, substitute:
Finally:
c) x’’+4x=0; x(0)=0; x’(0)=1
Let be the solution for the equation, then:
Substituting these equations in <em>c)</em>
This becomes the solution <em>m=α±βi</em> where <em>α=0</em> and <em>β=2</em>
Where <em>A</em> and <em>B</em> are constants. With x(0)=0; x’(0)=1:
Finally:
Answer:
From the given figure we can see that :---
MN||PO, MN=PO and MP=NO
Therefore, angle M=angle N (adjacent sides of the trapezoid)
angle M=angle N= (6×18)+20=108+20 =128°
angle O =(180°-128°)=52°
<h3>Hence, angle O is <u>52°.</u></h3>