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2 years ago

What is the range of this graph?

Mathematics

2 answers:

torisob [31]2 years ago

4 0

Can’t see the graph, try reposting it

Lelechka [254]2 years ago

3 0

Did you forgot to put your picture in the question

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The lengths of the sides of a triangle are 2x+1, 3x-2, and 4x-5. what is the perimeter in terms of x

STALIN [3.7K]

Answer:

Step-by-step explanation:

2X + 1 + 3X - 2 + 4X - 5 = 180

9X - 6 = 180

9X = 174

9 = 174

ـــــــــــــــــــــ

9 9

X = 19.333

8 0

3 years ago

What is the answer to 12x23

Triss [41]

The answer to 12x23 is 276

8 0

3 years ago

Write down the explicit solution for each of the following: a) x’=t–sin(t); x(0)=1

Kay [80]

Answer:

a) x=(t^2)/2+cos(t), b) x=2+3e^(-2t), c) x=(1/2)sin(2t)

Step-by-step explanation:

Let's solve by separating variables:

$x'=\frac{dx}{dt}$

a) x’=t–sin(t), x(0)=1

$dx=(t-sint)dt$

Apply integral both sides:

$\int {} \, dx=\int {(t-sint)} \, dt\\\\x=\frac{t^2}{2}+cost +k$

where k is a constant due to integration. With x(0)=1, substitute:

$1=0+cos0+k\\\\1=1+k\\k=0$

Finally:

$x=\frac{t^2}{2} +cos(t)$

b) x’+2x=4; x(0)=5

$dx=(4-2x)dt\\\\\frac{dx}{4-2x}=dt \\\\\int {\frac{dx}{4-2x}}= \int {dt}\\$

Completing the integral:

$-\frac{1}{2} \int{\frac{(-2)dx}{4-2x}}= \int {dt}$

Solving the operator:

$-\frac{1}{2}ln(4-2x)=t+k$

Using algebra, it becomes explicit:

$x=2+ke^{-2t}$

With x(0)=5, substitute:

$5=2+ke^{-2(0)}=2+k(1)\\\\k=3$

Finally:

$x=2+3e^{-2t}$

c) x’’+4x=0; x(0)=0; x’(0)=1

Let $x=e^{mt}$ be the solution for the equation, then:

$x'=me^{mt}\\x''=m^{2}e^{mt}$

Substituting these equations in c)

$m^{2}e^{mt}+4(e^{mt})=0\\\\m^{2}+4=0\\\\m^{2}=-4\\\\m=2i$

This becomes the solution m=α±βi where α=0 and β=2

$x=e^{\alpha t}[Asin\beta t+Bcos\beta t]\\\\x=e^{0}[Asin((2)t)+Bcos((2)t)]\\\\x=Asin((2)t)+Bcos((2)t)$

Where A and B are constants. With x(0)=0; x’(0)=1:

$x=Asin(2t)+Bcos(2t)\\\\x'=2Acos(2t)-2Bsin(2t)\\\\0=Asin(2(0))+Bcos(2(0))\\\\0=0+B(1)\\\\B=0\\\\1=2Acos(2(0))\\\\1=2A\\\\A=\frac{1}{2}$

Finally:

$x=\frac{1}{2} sin(2t)$

7 0

3 years ago

Find the Measure of angle O (see image) Only real answers, please

-Dominant- [34]

Answer:

From the given figure we can see that :---

MN||PO, MN=PO and MP=NO

Therefore, angle M=angle N (adjacent sides of the trapezoid)

$(8x - 16) = (6x + 20) \\ 2x = 36 \\ \boxed{x = 18}$

angle M=angle N= (6×18)+20=108+20 =128°

angle O =(180°-128°)=52°

<h3>Hence, angle O is 52°.</h3>

3 0

3 years ago

Which of these shows the result of using the first equation to substitute for y in the second equation, then combining like term

katen-ka-za [31]

Answer:

D. 8x=16

Step-by-step explanation:

If y=2x, then

2x+3y=16

2x+3(2x) =16

2x +6x=16

8x=16

5 0

3 years ago