This is actually an area problem:
The diameter of the circle is 6 which is the width of the sandbox and the radius is 1/2 of the diameter so r=3
Formula for area= π(r^2) or pi*radius squareThe area of the circle would be 9π which is 28.27
Then you subtract it from the area of the sandbox which is 6*10=60
60-28.27=31.73 which rounds to 32 square feet
Answer: C

6 0

3 years ago

Find the dimensions of a rectangle (in m) with perimeter 76 m whose area is as large as possible. (Enter the dimensions as a com

Anika [276]

Answer:

19,19

Step-by-step explanation:

It will be a square

76 / 4 = 19 m sides

7 0

2 years ago

Please help with 30!

Paladinen [302]

The equation of the graph y= $x^{3}-2x^{2} +3x-4$ has no symmetry

The equation of the graph y = $x^{3}-2x^{2} +3x-4$

Replace y with -y in the given equation

-y = $x^{3}-2x^{2} +3x-4$

When replacing y with -y gives the different equation. The equation is not symmetric with respect to x axis

Replace x with -x in the given equation

y = $(-x)^{3} -2(-x^{2} )-3(-x)-4$

y = $-x^{3}-2x^{2} +3x-4$

When replacing x with -x gives the different equation. The equation is not symmetric with respect to y axis

Replace x with -x and y with -y in the equation

-y = $(-x)^{3} -2(-x^{2} )-3(-x)-4$

-y = $-x^{3}-2x^{2} +3x-4$

When replacing x with -x and y with -y gives the different equation. The equation is not symmetry with respect to origin.

Hence, the equation of the graph y= $x^{3}-2x^{2} +3x-4$ has no symmetry

Learn more about symmetry here

brainly.com/question/16180199

#SPJ1

4 0

1 year ago

A+b×2%Can someone help me :)​

A+b×2%Can someone help me :)