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2 years ago

By what factor would your weight be multiplied if earth's diameter were 1/ 4 as big and earth's mass remained unchanged?.

Mathematics

1 answer:

GenaCL600 [577]2 years ago

3 0

Answer:

Step-by-step explanation:

Your weight is (roughly) proportional to the inverse of the square of the distance you are from the center of the earth. If that distance is reduced to 1/4 its previous value, then your weight will be multiplied by the factor ...

1/(1/4)² = 16

You would weigh 16 times as much.

_____

Additional comment

The distribution of mass within the earth also affects your weight.

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PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Kitty [74]

Answer: (-2, 5) and (2, -3)

Step-by-step explanation:

Graph the line y = -2x + 1 (which is in y = mx + b format) by plotting the y-intercept (b = 1) on the y-axis and then using the slope (m = -2) to plot the second point by going down 2 and right 1 unit from the first point:

y - intercept = (0, 1) 2nd point = ( -1, 1).

Graph the parabola y = x² - 2x - 3 by first plotting the vertex and then plotting the y-intercept (or some other point):

$y = x^2-2x-3\quad \rightarrow \quad a=1,\ b=-2,\ c=-3\\\\\text{axis of symmetry:}\ x = \dfrac{-b}{2a}\ \longrightarrow \ x=\dfrac{-(-2)}{2(1)}=\dfrac{2}{2}=1\\\\\text{y-value of vertex:}\ f(1) = (1)^2-2(1)-3\quad \longrightarrow \quad y = 1 - 2 - 3=-4\\\\\text{y-intercept:}\ f(0)= (0)^2-2(0)-3\ \longrightarrow \ y=0 - 0 - 3 = -3 \\$

vertex = (1, -4) 2nd point (y-intercept) = (0, -3)

see attached - the graphs intersect at two points: (-2, 5) and (2, -3)

8 0

2 years ago

5 is a prime number of 2475 what are the other two numbers

ArbitrLikvidat [17]

$2475=3^2\cdot5^2\cdot11$

The two other prime factors are 3 and 11

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2 years ago

A projectile is launched into the air. The function h(t) = –16t2 + 32t + 128 gives the height, h, in feet, of the projectile t s

Zinaida [17]

Answer:

t = 4 seconds

Step-by-step explanation:

The height of the projectile after it is launched is given by the function :

$h(t)=-16t^2+32t+128$

t is time in seconds

We need to find after how many seconds will the projectile land back on the ground. When it land, h(t)=0

So,

$-16t^2+32t+128=0$

The above is a quadratic equation. It can be solved by the formula as follows :

$t=\dfrac{-b\pm \sqrt{b^2-4ac} }{2a}$

Here, a = -16, b = 32 and c = 128

$t=\dfrac{-32\pm \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}\\\\t=\dfrac{-32+ \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}, \dfrac{-32\- \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}\\\\t=-2\ s\ \text{and}\ 4\ s$

Neglecting negative value, the projectile will land after 4 seconds.

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3 years ago

Byers Auto is selling a new minivan that has a base price of $22,510. The

eduard

Answer:
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Leya [2.2K]

Answer:

Step-by-step explanation:

It is the highest exponent value.

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