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klasskru [66]
2 years ago
11

The graph shows the cost of renting skates. Sadie rents a pair of skates at 10 A.M. How much will she pay if she returns the ska

tes by 1 P.M.?
How much will she pay if she returns them at 1:15 P.M.?


1 PM: ??

1:15 PM: ??

Mathematics
1 answer:
stiv31 [10]2 years ago
5 0

Answer: 1 PM = $8

1:15 PM = $9.0

Step-by-step explanation:

a. Since Sadie rents a pair of skates at 10 A.M and returned the skates by 1 P.M, this means the hours spent was 3 hours. Therefore, based on the graph, for 3 hours rented, he will pay $8

The amount that she will pay if she returns them at 1:15 P.M. will be equal to the value of 3 hours 15 minutes which will be:

= $8 + $1.0

= $9.00

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Find the vertical and horizontal asymptotes, domain, range, and roots of f (x) = -1 / x-3 +2.
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Answer:

Vertical asymptote: x=3

Horizontal asymptote: f(x) =2

Domain of f(x) is all real numbers except 3.

Range of f(x) is all real numbers except 2.

Step-by-step explanation:

Given:

Function:

f (x) = -\dfrac{1 }{ x-3} +2

One root, x = 3.5

To find:

Vertical and horizontal asymptote, domain, range and roots of f(x).

Solution:

First of all, let us find the roots of f(x).

<em>Roots of f(x) means the value of x where f(x) = 0</em>

0= -\dfrac{1 }{ x-3} +2\\\Rightarrow 2= \dfrac{1 }{ x-3}\\\Rightarrow 2x-2 \times 3=1\\\Rightarrow 2x=7\\\Rightarrow x = 3.5

One root, x = 3.5

Domain of f(x) i.e. the values that we give as input to the function and there is a value of f(x) defined for it.

For x = 3, the value of f(x) \rightarrow \infty

For all, other values of x , f(x) is defined.

Hence, Domain of f(x) is all real numbers except 3.

Range of f(x) i.e. the values that are possible output of the function.

f(x) = 2 is not possible in this case because something is subtracted from 2. That something is \frac{1}{x-3}.

Hence, Range of f(x) is all real numbers except 2.

Vertical Asymptote is the value of x, where value of f(x) \rightarrow \infty.

-\dfrac{1 }{ x-3} +2 \rightarrow \infty

It is possible only when

x-3=0\\\Rightarrow x=3

\therefore vertical asymptote: x=3

Horizontal Asymptote is the value of f(x) , where value of x \rightarrow \infty.

x\rightarrow \infty \Rightarrow \dfrac{1 }{ x-3} \rightarrow 0\\\therefore f(x) =-0+2 \\\Rightarrow f(x) =2

\therefore Horizontal asymptote: f(x) =2

Please refer to the graph of given function as shown in the attached image.

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3 years ago
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